The factorization of A is y = (x - 8)(x + 7).
The factorization of B is y = (x + 1)(x - 4)(x - 5)
In order to find these, you must first find where each graph crosses the x-axis. In the first problem it does so at 8 and -7. In order to find the correct parenthesis for those, you need to write it out as a statement and then solve for 0.
x = 8 ---> subtract 8 from both sides
x - 8 = 0
This means we use (x - 8) in our factorization.
You then need to repeat the process until you have all the pieces. In the second problem, there will be 3 instead of 2 since it crosses the axis 3 times.
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Step-by-step explanation:
The answer would be 101
Steps:
2+8=10
10x10=100 (because of the exponent)
100+1=101
There are 7 chairs in each row length.
Step-by-step explanation:
Let number of chairs in 1 row be 'x'.
Let total number of chairs be 'y'.
Given:
Hue can form 6 rows of a given length with 3 chairs left over.
It means that Total number of chairs is equal to chairs in 1 rows multiplied by number of rows which is 6 plus number of chairs which is left which is 3.
Framing in equation form we get.
Also Given:
Hue can form 8 rows of that same length if she gets 11 more chairs.
It means that Total number of chairs is equal to chairs in 1 rows multiplied by number of rows which is 8 minus number of chairs which is required more which is 11.
Framing in equation form we get.
From equation 1 and equation 2 we can say that L.H.S is same.
So according to law of transitivity we get;
Combining like terms we get;
Using Subtraction and Addition property we get;
Now Using Division Property we will divide both side by 2.
Hence there are 7 chairs in each row length.