Simplify the following:
(3 sqrt(2) - 4)/(sqrt(3) - 2)
Multiply numerator and denominator of (3 sqrt(2) - 4)/(sqrt(3) - 2) by -1:
-(3 sqrt(2) - 4)/(2 - sqrt(3))
-(3 sqrt(2) - 4) = 4 - 3 sqrt(2):
(4 - 3 sqrt(2))/(2 - sqrt(3))
Multiply numerator and denominator of (4 - 3 sqrt(2))/(2 - sqrt(3)) by sqrt(3) + 2:
((4 - 3 sqrt(2)) (sqrt(3) + 2))/((2 - sqrt(3)) (sqrt(3) + 2))
(2 - sqrt(3)) (sqrt(3) + 2) = 2×2 + 2 sqrt(3) - sqrt(3)×2 - sqrt(3) sqrt(3) = 4 + 2 sqrt(3) - 2 sqrt(3) - 3 = 1:
((4 - 3 sqrt(2)) (sqrt(3) + 2))/1
((4 - 3 sqrt(2)) (sqrt(3) + 2))/1 = (4 - 3 sqrt(2)) (sqrt(3) + 2):
Answer: (4 - 3 sqrt(2)) (sqrt(3) + 2)
Whats the normal arm span for these heights? : 4'10,4'11,5'0,5'4,5'5,5,'7,5'8,5'9,5'10,5'11,6'0
Svetllana [295]
In adults, the arm span is approximately 5 cm greater than the height in adult males and 1.2 cm in
adult females. To calculate the arm span for the heights given, we add
5cm to their height. The following are the results:
Height Arm Span Length (in cm)
4’10 152.32
4’11 154.86
5’0 157.4
5’4 167.56
5’5 170.10
5’7 175.18
5’8 177.72
5’9 180.26
5’10 182.80
5’11 185.34
6’0 187.88
To add, the total measurement of the length from the furthermost
part of an individual's arms to the other end
when raised equidistant to the ground at shoulder height at a 90º angle
is called the arm span or wingspan.
Answer:
See below
Step-by-step explanation:
For a parallelogram m < A = m < C so:-
75 + 5x = 87 + 3x
2x = 12
x = 6
and m< A = 75 + 30 = 105
and m < C = 87 + 18 = 105
Now if the other 2 angles are = 75 degrees( that is the same side angles add up to 180 degrees) we have proved that it is a parallelogram.
m < B = m < D
111 - 6x = 39 + 6x
-12x = -72
x = 6
m < B = 111 - 36 = 75 and m < D = 39 + 36 = 75
So this has been proved.
Answer: 55-1/2w=p
Step-by-step explanation: 55 is the starting weight. Therefore, you need to subtract 55 by 1/2 (the amount of weight he loses each week) times each week. This will determines the weight- (p).
0.999993283193413 is the answer. You may have to round.
