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schepotkina [342]
3 years ago
6

Can someone solve this

Mathematics
1 answer:
zysi [14]3 years ago
3 0
You know how Soh Cah Toa applies to right triangles; you can assign the adjacent side = 4 and hypotenuse = 7

CosФ = (adjacent) / (hypotenuse)

Then with the Pythagorean theorem
4² + b² = 7²
16 + b² = 49
b² = 49 - 16
b² = 33
b = √(33)

So "b" is the opposite side.

SinФ = (opposite) / (hypotenuse) = √(33)/7
TanФ = (opposite) / (adjacent) = √(33)/4
You might be interested in
Consider the equation and the relation “(x, y) R (0, 2)”, where R is read as “has distance 1 of”. For example, “(0, 3) R (0, 2)”
Leviafan [203]

Answer:

The equation determine a relation between x and y

x = ± \sqrt{1-(y-2)^{2}}

y = ± \sqrt{1-x^{2}}+2

The domain is 1 ≤ y ≤ 3

The domain is -1 ≤ x ≤ 1

The graphs of these two function are half circle with center (0 , 2)

All of the points on the circle that have distance 1 from point (0 , 2)

Step-by-step explanation:

* Lets explain how to solve the problem

- The equation x² + (y - 2)² and the relation "(x , y) R (0, 2)", where

 R is read as "has distance 1 of"

- This relation can also be read as “the point (x, y) is on the circle

 of radius 1 with center (0, 2)”

- “(x, y) satisfies this equation , if and only if, (x, y) R (0, 2)”

* <em>Lets solve the problem</em>

- The equation of a circle of center (h , k) and radius r is

  (x - h)² + (y - k)² = r²

∵ The center of the circle is (0 , 2)

∴ h = 0 and k = 2

∵ The radius is 1

∴ r = 1

∴ The equation is ⇒  (x - 0)² + (y - 2)² = 1²

∴ The equation is ⇒ x² + (y - 2)² = 1

∵ A circle represents the graph of a relation

∴ The equation determine a relation between x and y

* Lets prove that x=g(y)

- To do that find x in terms of y by separate x in side and all other

  in the other side

∵ x² + (y - 2)² = 1

- Subtract (y - 2)² from both sides

∴ x² = 1 - (y - 2)²

- Take square root for both sides

∴ x = ± \sqrt{1-(y-2)^{2}}

∴ x = g(y)

* Lets prove that y=h(x)

- To do that find y in terms of x by separate y in side and all other

  in the other side

∵ x² + (y - 2)² = 1

- Subtract x² from both sides

∴ (y - 2)² = 1 - x²

- Take square root for both sides

∴ y - 2 = ± \sqrt{1-x^{2}}

- Add 2 for both sides

∴ y = ± \sqrt{1-x^{2}}+2

∴ y = h(x)

- In the function x = ± \sqrt{1-(y-2)^{2}}

∵ \sqrt{1-(y-2)^{2}} ≥ 0

∴ 1 - (y - 2)² ≥ 0

- Add (y - 2)² to both sides

∴ 1 ≥ (y - 2)²

- Take √ for both sides

∴ 1 ≥ y - 2 ≥ -1

- Add 2 for both sides

∴ 3 ≥ y ≥ 1

∴ The domain is 1 ≤ y ≤ 3

- In the function y = ± \sqrt{1-x^{2}}+2

∵ \sqrt{1-x^{2}} ≥ 0

∴ 1 - x² ≥ 0

- Add x² for both sides

∴ 1 ≥ x²

- Take √ for both sides

∴ 1 ≥ x ≥ -1

∴ The domain is -1 ≤ x ≤ 1

* The graphs of these two function are half circle with center (0 , 2)

* All of the points on the circle that have distance 1 from point (0 , 2)

8 0
3 years ago
Complete the function using the function y=-2x -6<br> -2<br> 0<br> 2<br> 4
Mariana [72]
I need more info please!!
5 0
3 years ago
There is only three options someone help
Pepsi [2]

Answer:

Answer is Option 2

Step-by-step explanation:

Triangles equal to 180 degrees in total. So it is 55+54+x+74=180

The simplified version that I just wrote is Option 2

7 0
3 years ago
Find the loss or gain % when 20 pens are sold for the CP of 25 pen.​
mel-nik [20]

Answer:

20% gained

Step-by-step explanation:

25 - 20 = 5

5 / 25 * 100 = 20%

6 0
2 years ago
Please help me with this problem, please
Harman [31]

Answer:

sin(x) = 5/13

cos(y) = 5/12

Therefore, sin(x) = cos(y)

Step-by-step explanation:

Trig ratios:

sin(\theta)=\dfrac{O}{H}\\\\\\cos(\theta)=\dfrac{A}{H}\\\\\\tan(\theta)=\dfrac{O}{A}

where \theta is the angle, O is the measure of the side opposite the angle, A is the measure of the side adjacent to the angle and H is the hypotenuse, of a right triangle

We have been given the measures of the two legs, so we can find the measure of the hypotenuse by using Pythagoras' Theorem a^2+b^2=c^2

(where a and b are the legs and c is the hypotenuse of a right triangle)

\implies 5^2+12^2=c"\\\\\implies 169=c^2\\\\\implies c=\sqrt{169}\\\\ \implies c=13

Now we can use the trig ratios:

\implies sin(x)=\dfrac{5}{13}

\implies cos(y)=\dfrac{5}{13}

Therefore, sin(x) = cos(y)

8 0
2 years ago
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