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maksim [4K]
3 years ago
12

The sum of three consecutive integers is -78. determine the smallest integer.

Mathematics
1 answer:
sweet [91]3 years ago
4 0
Lets x is the 1st consecutive even integers
      x +2 :the 2nd consecutive even integers
      x +4: the 3rd consecutive even integers

So sum of all 3 equals -78 then
x + (x+2) + (x+4) = -78
x + x + 2 + x + 4 = -78
Simplify
3x + 6 = -78
Subtract (-6) to both sides
3x +6 -6 = -78 - 6
Simplify
3x = -84
Divided both sides by 3
3x/3 = -84/3

x = -28
x + 2 =  -28 + 2 = -26
x +4 = - 28 + 4 = -24

Double check: -28 + -26 + -24 = -78

So the three consecutive even integers are: -24, -26, -28

The smallest integer would be -28
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Will wanted to solve the problem
Bezzdna [24]

The large division mathematical problem can be solved using partial

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The methods that could be used to find the quotient are;

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C. <u>Subtract (20 × 12) from 468 to get 228. Subtract (10 × 12) from 228 to get </u>

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Reason:

The division of 468 by 12 using partial quotient gives;

12|\overline{468}

<u>   </u>{}<u> -360</u>  ← 30 × 12

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<u>   </u>{}<u>   -108</u>  ← 9 × 12

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Therefore, option B. can be used to find the quotient;

Option B: Subtract (30 × 12) from 468; 468 - 30 to get 108. Subtract (9 ×

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The method in option C which is expressed as follows;

468 - 20 × 12 = 228

228 - 10 × 12 = 108

108 - 3 × 12 = 72

72 - 6 × 12 = 0

Therefore, option is C. could be used and the statement is expressed as follows;

Subtract (20 × 12) from 468 to get 228. 468 - (20 × 12) = 228

Subtract (10 × 12) from 228 to get 108. 228 - (10 × 12) = 128

Subtract (3 × 12) from 108 to get 72. 108 - (3 × 12) = 72

Subtract (6 × 12) from 72 to get a 0 remainder.

Learn more here:

brainly.com/question/19306817

brainly.com/question/13757061

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