2 years ago

6x + 5y = 8 5x + 5y = 15

Mathematics

1 answer:

Flura [38]2 years ago

8 0

Philiphines

Step-by-step explanation:

lang ang malakas

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1+2=21, 2+3=36,3+4=43,4+5=?

Anni [7]

1+2=21, 2+3=36, 3+4=43, 4+5=52.

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3 years ago

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A student is taking two courses, history and math. the probability the student will pass the history course is 0.59, and the pro

natka813 [3]

Probability of passing history course = 0.59

Probability of passing math course = 0.60

Probability of passing both courses = 0.49

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3 years ago

A line passing through (-1 7) and (2, 10)

Inessa05 [86]

Answer:B

Step-by-step explanation:

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3 years ago

Find the derivative of sinx/1+cosx, using quotient rule

Mrrafil [7]

Answer:

f'(x) = -1/(1 - Cos(x))

Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

$f'(x) = \frac{h'(x)*k(x) - k'(x)*h(x)}{k^2(x)}$

In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

h'(x) = Cos(x)

And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

$f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}$

Now we can simplify that:

$f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}$

And we know that:

cos^2(x) + sin^2(x) = 1

then:

$f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}$

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3 years ago

Lucy made $323 for 17 hours of work.

saveliy_v [14]

19 minutes I think just divide 323 and 17

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2 years ago