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Ludmilka [50]
3 years ago
13

Which is an equation of a circle with center (2, −10) and radius 3

Mathematics
1 answer:
stepladder [879]3 years ago
6 0
(x - a)^2 + (y - b)^2 = r^2 is a circle with centre at (a, b) and radius of r
The correct answer is (x - 2)^2 + (y + 10)^2 = 9 ie the first one
You might be interested in
-5x-12>6x-4 Solve the inequality and give the answer in interval notation.
lora16 [44]

-5x-12>6x-4

To Solve the inequality we need to get x alone

-5x-12>6x-4

first we remove -12, for that we add 12 on both sides

-5x-12+12>6x-4+12

-5x > 6x +8

Now subtract 6x from both sides

-5x -6x> 6x-6x +8

-11x > 8

Divide by -11. when we divide by -11 we flip the inequality . so > becomes <

x < -\frac{8}{11}

We need to give the answer in interval notation.

x is less than -8/11 so x value starts from -8/1  and goes to -infinity(left)

So interval notation is (-∞, -\frac{8}{11})

7 0
3 years ago
Find the area of each figure. Use 3.14
grigory [225]
<h3>Answer:  23.13 square meters</h3>

===============================================================

Explanation:

The top and bottom semicircles can be joined to form a full circle. The same can be said about the left and right semicircles. Each circle has diameter 3 and radius 1.5

The area of one circle is

A = pi*r^2

A = 3.14*(1.5)^2

A = 7.065

So two circles doubles to 2*7.065 = 14.13 square meters in area.

Then the last step is to add on the area of the 3 by 3 square (area 3*3 = 9) to get 14.13+9 = 23.13

This area is approximate because pi = 3.14 is approximate. Use more decimal digits in pi to get a more accurate area. However, your teacher wants you to use this specific value so it's best to stick with 23.13

8 0
3 years ago
Read 2 more answers
ONE OF THE FIRST WALKING ROBOTS HAD A TOP
vazorg [7]

Answer:

? can you explain this a little better

Step-by-step explanation:

3 0
3 years ago
Bobby has already ran 1 mile on his own, and he expects to run 1 mile during each track practice. How many track practices would
german

Answer:

In order to have ran 33 miles, Bobby would have to attend <em>32 track practices.</em>

Step-by-step explanation:

Solving this problem entails of uncovering the amount of track practices Bobby must attend in order to have ran 33 miles. Start by reading the problem carefully to break down the information provided.

You can see that Bobby has already ran one mile on his own. This is important to remember for later. The problem also states that he expects to run one mile at every track practice.

Setting up an equation will help us solve. Here is how we could set up the equation:

(<em>amount of miles already ran</em> = 1) + (<em>number of track practices</em> = x) = (<em>total miles to run</em> = 33)

1 + x = 33

The equation is now in place. You can solve this, or isolate <em>'x',</em> by using the subtraction property of equality. This means we will subtract one from both sides of the equation, thus isolating the variable.

1 + x = 33

1 - 1 + x = 33 - 1

x = 32

The variable is the only term left on the left side of the equation. This means Bobby must attend track practice <em>32 times</em> in order to have ran 33 miles.

8 0
3 years ago
The line that passes through the points (9,1) and (5,5) intersects the y-axis at (0,5).
Ilia_Sergeevich [38]
The stament are true I think
6 0
3 years ago
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