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2 years ago

Please answer. I have attached the picture of the question and I promise I will give brainliest.

Mathematics

1 answer:

Vaselesa [24]2 years ago

8 0

Answer:

first is the chart so for the time row its 4, 8, 12, 16, 20 & distance is 3, 6, 9, 12, 15

I added the complete graph down below, basically what i did wasplot the points from the chart so (4,3), (8,6), (12,9), (16, 12), and (20,15)

so for example for (4,3) you would first find 4 on the x-axis or the time line and then find 3 on the y-axis and so on let me know if you can see the picture:)

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The answer to a,b and c

GuDViN [60]

Answer:

16/45; 4/45; 1125

Step-by-step explanation:

Since you know that 4/9 and 1/5 are used, make them common denominators. So 4/9 would turn into 20/45 and 1/5 would be 9/45. It results in 29/45, but that is the amount spent, so you would subtract 45-29/45, resulting in 16/45. For B, you know that she spent 3/4 of the savings, so you know that 1/4 is not being spent. So use 1/4 multiplied by 16/45 from part A to get 4/45. For C, you know that 4/45 is $100, so I multiplied 45x100 to get 4500 and then divided by 4 to get 4500/4.

8 0

2 years ago

Which of the following do not have precise definitions in geometry. Select the two correct answers

guapka [62]

Answer:

2 and 5

Point and line.

Step-by-step explanation:

In geometry, there are many terms and jargons Mathematicians make use of.

Angle is one of the term used in geometry which depicts any form of inclination.

Segment is also use to analyze and to solve many questions.

Lines are used to join one segment or the other.

Point and ray are also used but are majorly used in optics

Asking that Which of the following do not have precise definitions in geometry.

The best answer are point and line.

Because there is no specific definition for the two variables.

7 0

2 years ago

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is: