Answer:
x = - 3, x = 
Step-by-step explanation:
Given
4x² + 2x - 30 = 0 ( divide through by 2 )
2x² + x - 15 = 0
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 2 × - 15 = - 30 and sum = + 1
The factors are + 6 and - 5
Use these factors to split the x- term
2x² + 6x - 5x - 15 = 0 ( factor the first/second and third/fourth terms )
2x(x + 3) - 5(x + 3) = 0 ← factor out (x + 3) from each term
(x + 3)(2x - 5) = 0
Equate each factor to zero and solve for x
x + 3 = 0 ⇒ x = - 3
2x - 5 = 0 ⇒ 2x = 5 ⇒ x =
<span>So we want to know the new coordinates for the vertex A'(x,y) if we know that the vertex A is at A(-1,2) and vertex B is at B(1,5) and that the triangle ABC is translated 6 units up and 3 units left. So the method is simply to add units 6 to x and 3 to y of A to get A'. Going left means we need to go to negative x direction and going up means we need to go to positive y direction. So: A'(-1-3,2+6) and that is: A'(-4,8). </span>
Answer:
The answer is option D.
Step-by-step explanation:
f(x) = x² + 2x
g(x) = 2x
To find (ƒ ∘ g)(2) first find (ƒ ∘ g)
To find (ƒ ∘ g) wherever you see x in f(x) replace it with g(x)
That's
(ƒ ∘ g) = (2x)² + 2(2x)
= 4x² + 4x
Substitute 2 into the expression
That's
(ƒ ∘ g)(2) = 4(2)² + 4(2)
= 4(4) + 8
= 16 + 8
= 24
Hope this helps you.
Multiply by 3 on both sides of the equation to get
by+2=3c
Then subtract 2 from both sides to get
by=3c-2
Divide by b on both sides to get
y=(3c-2)/b
Given
consider substituting 
to get a proper quadratic equation,
Solve for 
; we can factorize to get
Solve for 
:
The first equation has no real solution, since 
for all non-zero . Proceeding with the second equation, we get
If we want to find all complex solutions, we take 
so that the first equation above would have led us to
