I believe the answer would be $12,900
Answer:
The weight of the block that Katie has is 16 1/3 pounds
Step-by-step explanation:
<u>Katie has: 4 full cement blocks and 4/6 (or 2/3 ) of the normal size of a cement block</u>
For one full block, it weighs 3 2/4 ( or 1/2) pounds, if you want to find the answer of the question, you need to multiply the weight with the cement blocks that Katie have.
<u>First do the four full cement blocks:</u>
4 * 3 2/4 = ?
4 * 14/4 = ?
Cancel the 4 that is being multiplied and the 4 that is being divided by 14.
= 14.
<u>Now do the 4/6 (or 2/3) cement block:</u>
2/3 * 3 2/4 = ?
2/3 * 14/4 = ?
Multiply the fractions together:
= 28/12
= 2 1/3
<u>Finally, you add up the full blocks and the 2/3 cement block to get your answer:</u>
2 1/3 + 14 = 16 1/3
The weight of the block that Katie has is 16 1/3 pounds
Answer:
-7x
Step-by-step explanation:
==> -12x + 5x.
==> -12+5xx
==> -7x
Answer:
x = 5
Step-by-step explanation:
Δ EAB and Δ EDC are similar by the AA postulate , so the ratio of corresponding sides are in proportion , that is
= 
, substitute values
= 
( cross- multiply )
10(x + 3) = 4(2x + 10 ) ← distribute parenthesis on both sides
10x + 30 = 8x + 40 ( subtract 8x from both sides )
2x + 30 = 40 ( subtract 30 from both sides )
2x = 10 ( divide both sides by 2 )
x = 5
Answer:
hole at x=-3
Step-by-step explanation:
The hole is the discontinuity that exists after the fraction reduces. (Still doesn't exist for original of course)
The discontinuities for this expression is when the bottom is 0. x^2-9=0 when x=3 or x=-3 since squaring either and then subtracting 9 would lead to 0.
So anyways we have (x+3)/(x^2-9)
= (x+3)/((x-3)(x+3))
Now this equals 1/(x-3) with a hole at x=-3 since the x+3 factor was "cancelled" from the denominator.
