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Tatiana [17]
3 years ago
7

A bag contains 6 red marbles, 3 blue marbles, and 7 green marbles. You choose one then a second without replacement. What is the

probability that you draw 2 greens?
Mathematics
1 answer:
timama [110]3 years ago
6 0
3/7 I think, I'm not exactly sure. But, hope this helps!! (:
You might be interested in
Yall im almost done pls HELP
S_A_V [24]

Answer:

61 degrees

Step-by-step explanation:

==>Given ∆MNO,

MO = 18,

MN = 6

m<O = 17°

==>Required:

Measure of <N

==>SOLUTION:

Use the sine formula for finding measure of angles which is given as: Sine A/a = Sine B/b = Sine C/c

Where,

Sine A = 17°

a = 6

Sine B = N

b = 18

Thus,

sin(17)/6 = sin(N)/18

Cross multiply

sin(17)*18 = sin(N)*6

0.2924*18 = 6*sin(N)

5.2632 = 6*sin(N)

Divide both sides by 6

5.2632/6 = sin(N)

0.8772 = sin(N)

sin(N) = 0.8772

N = sin^-1(0.8772)

N ≈ 61° (approximated)

8 0
3 years ago
PLEASE HURRY!!!!!!
Anni [7]

Answer:

Step-by-step explanation:

The manager visits a park and interviews people who are waiting to use the tennis courts.

7 0
3 years ago
Multiply 2(x+3)/x(x-1)*4x(x+2)/10(x+3)
KIM [24]

Answer:

The expression simplifies to \frac{4(x+2)}{5(x-1)}.

Step-by-step explanation:

The expression

\frac{2(x+3)}{x(x-1)} *\frac{4x(x+2)}{10(x+3)}

can be rearranged and written as

\frac{8x(x+3)(x+2)}{10x(x-1)(x+3)}.

In this form the (x+3) terms in the numerator and in the denominator cancel to give

\frac{8x(x+2)}{10x(x-1)}.

The x's are present both in the numerator and in the denominator, so they also cancel, and the fraction \frac{8}{10} simplifies to \frac{4}{5}, so finally our expression becomes:

\boxed{\frac{4(x+2)}{5(x-1)}}

Which is our answer:)

6 0
3 years ago
A certain breed of mouse was introduced onto a small island with an initial population of 320 mice, and scientists estimate that
Viefleur [7K]
Y=2x+320
x being the number of years and 320 being the initial population of mice
7 0
3 years ago
1. If A = {a, b, c, d}, B={c, d, e, f}, C={x, y, z} find (A-B)​
vitfil [10]

Answer

here

A={a,b,c,d}

B={c,d,e,f}

C={x,y,z}

A-B={e,f}

8 0
1 year ago
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