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3 years ago

10

How would you prove this using a flow chart?

1 answer:

Genrish500 [490]3 years ago

6 0

$\triangle BCA\sim\triangle DEA\ (AA)\\\text{therefore the ratios of the lengths of their corresponding sides are equal}\\\\\dfrac{BC}{AC}=\dfrac{DE}{AE}\ \ \ |\text{cross multiply}\\\\BC\cdot AE=AC\cdot DE\ \ \ \ |:BC\\\\AE=\dfrac{AC\cdot DE}{BC}\ \ \ \ |:AC\\\\\dfrac{AE}{AC}=\dfrac{DE}{BC}\to\dfrac{DE}{BC}=\dfrac{AE}{AC}$

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