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Sav [38]
3 years ago
6

(7p^(2)+3p)-(5p^(2)+4) solve for standard form and show how you got it

Mathematics
1 answer:
inna [77]3 years ago
5 0

\huge \boxed{\mathfrak{Question} \downarrow}

  • ( 7 p ^ { 2 } + 3 p ) - ( 5 p ^ { 2 } + 4 ). Solve for standard form.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

( 7 p ^ { 2 } + 3 p ) - ( 5 p ^ { 2 } + 4 )

To find the opposite of 5p²+4, find the opposite of each term inside the bracket.

7p^{2}+3p-5p^{2}-4

Combine 7p² and -5p² to get 2p².

\boxed{ \boxed{ \bf \: 2p^{2}+3p-4 }}

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a paperweight is in the shape of a pyramid. The base is a square with sides of 1.5 centimeters. The height of the paperweight is
Alona [7]
The answer is 1.5x3 which is 4.5 i am pretty sure.
4 0
3 years ago
Lucy draws a rectangle that is not a square. The perimeter of the rectangle can be
shusha [124]
Answer is i think c
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8 0
2 years ago
The total cost of painting of four walls of a square hall at Rs. 40 per sq. m. is Rs. 12000. If the hall contains 600 m³ of air,
astra-53 [7]

Answer:

The height of the hall is 9.375 meters

Step-by-step explanation:

The rate at which the walls of the square hall are painted, R = Rs. 40 per sq. m.

The total cost of painting the square hall, C = Rs. 12,000

The volume of air contained in the hall, V = 600 m³

The surface area of the four walls of the hall, A = C/A

∴ A = Rs. 12,000/(Rs. 40/m²) = 300 m²

Let 's' represent the length of sides of the square hall, and let 'h' represent the height of the square wall, we have;

The volume of the hall, V = s² × h

The surface area of the wall, A = 4 × s × h

Therefore, we get;

A = 300 = 4 × s × h

V = 600 = s² × h

V/A = 600/300 = 2 = s² × h/(4 × s × h) = s/4

s/4 = 2

s = 4 × 2 = 8

The side length of the square hall, s = 8 m.

From the area, A = 4 × s × h, we get;

A = 300 = 4 × 8 × h

h = 300/(4 × 8) = 9.375

The height of the hall, h = 9.375 m.

8 0
3 years ago
The original rectangle has a perimeter of 16
zaharov [31]

As we can see that the sides of the rectangle have been doubled

6.2 ft changed to 12.4 ft

Now when the sides have been doubled

the Perimeter will also be doubled

So the perimeter of new rectangle should be the double the perimeter of old rectangle

So perimeter of new rectangle = 2 (16 ) = 32 feet

Option C is correct

7 0
3 years ago
2, 4, 13, 49, 193,
PolarNik [594]

If we begin with the first term, 2, mult. it by 4 and then subtract 3, we get 5 (not 4, as shown).

If we begin with 4, mult. it by 4 and then subtract 3, we get 13. This agrees with the terms of the given sequence.

If we begin with 13, mult. it by 4 and then subtract 3, we get 49. This agrees with the terms of the given sequence.

Remove the first term, 2, and then the remaining terms follow the given procedure for finding terms.


7 0
3 years ago
Read 2 more answers
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