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k0ka [10]
3 years ago
11

Ten friends want to play a game. They must be divided into three teams with three people in each team and one field judge. In ho

w many ways can they do it?

Mathematics
2 answers:
sertanlavr [38]3 years ago
6 0

Answer:

It is the number of ways you can arrange the letters AAABBBCCCF, indicating that three players are on team A, three on team B, and three on team C, with one the field judge F.

Each different arrangement represents one of the ways you can form three teams of 3 with a field judge.

That number of arrangments, and therefore the number of ways to divide the players as required, is

rodikova [14]3 years ago
6 0
2800

I’ve done this problem before, and the answer is right.

Explanation:
Look at number 10

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So we know if x=large dogs and y=small dogs, then x+y=49.
Next we are told that there are 36 MORE small dogs than large dogs. We can take that more meaning addition, and x being our value for large dogs. So y=x+36.
After that we now know what value we can plug in for y. So x+x+36=49.
We can then simplify it to 2x+36=49.
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Followed by dividing both sides by 2, gives you x=6.5. Or 6.5 large dogs.
Now we can plug this into our formula for the small dogs (y=x+36) to give us y=6.5+36, which simplifies to y=42.5. Or 42.5 small dogs. Which is our answer.
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