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k0ka [10]
3 years ago
11

Ten friends want to play a game. They must be divided into three teams with three people in each team and one field judge. In ho

w many ways can they do it?

Mathematics
2 answers:
sertanlavr [38]3 years ago
6 0

Answer:

It is the number of ways you can arrange the letters AAABBBCCCF, indicating that three players are on team A, three on team B, and three on team C, with one the field judge F.

Each different arrangement represents one of the ways you can form three teams of 3 with a field judge.

That number of arrangments, and therefore the number of ways to divide the players as required, is

rodikova [14]3 years ago
6 0
2800

I’ve done this problem before, and the answer is right.

Explanation:
Look at number 10

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A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
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Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

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From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

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\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

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Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

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