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Amanda [17]
3 years ago
11

Label 4 and their opposites on a number line

Mathematics
1 answer:
konstantin123 [22]3 years ago
4 0
The opposite of 4 is -4. so, on your number line, graph -4 and 4.
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Which phase of the sdlc gathers business requirements?.
Lyrx [107]

Answer:

Analysis phase

Step-by-step explanation:

involves analyzing end-user business requirements and refining project goals into defined functions and operations of the intended system

hope this helps

5 0
2 years ago
PLEAAASEEEE HEELLPPP ME ASAPPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Leya [2.2K]
If you could verify D), I could give you a more definite answer. As for now, choose A and D if you can choose more than one. If you can't, choose A.
3 0
4 years ago
Read 2 more answers
A random sample of 20 healthy adults was collected and their body temperatures were measured in degrees Fahrenheit. The data can
castortr0y [4]

Answer:

Step-by-step explanation:

Hello!

You need to test the hypothesis that "the average temperature for healthy adults is not equal to 98.6"

The variable of interest is

X: The body temperature of a healthy adult. (Fahrenheit)

And the parameter of interest is the population mean, μ.

The statistic hypotheses are:

H₀: μ = 98.6

H₁: μ ≠ 98.6

α:0.05

Assuming that the variable has a normal distribution you have to use a one-sample t-statistic for this test.

Attached to the answer is the data of body temperature of n=19 healthy adults. Since you didn't copy the raw data for your exercise I'll use this to answer the question.

Using the data the sample mean and standard deviation are:

X[bar]= 98.12

S= 0.69

t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~~t_{n-1}

t_{H_0}= \frac{98.12-98.6}{\frac{0.69}{\sqrt{19} } } = -3.03

This test is two-tailed, using the critical value approach, you have the rejection region divided into two tails determined by two critical values:

t_{n-1;\alpha /2}= t_{18;0.025}= -1.965

t_{n-1;1-\alpha /2}= t_{18;0.975}= 1.965

Decision rule:

If t_{H_0} ≤ -1.965 or if t_{H_0} ≥ 1.965, the decision is to reject the null hypothesis.

If -1.965 < t_{H_0} < 1.965, the decision is to not reject the null hypothesis.

The calculated statistic is less than the lower critical value, the decision is to reject the null hypothesis.

Using a significance level of 5%, there is enough evidence to reject the null hypothesis. Then you can conclude that the true mean body temperature for healthy adults is not equal to the traditional 98.6F.

I hope this helps!

7 0
4 years ago
Jack Drove 40 1/2 miles. He used 1 1/2 gallons of gasoline. What is the unit rate for miles per gallon
Maurinko [17]

Answer: dang I learned this and forgot

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A and b are monomials where a = 125 and b = 27p12. what is the factored form of a – b?
torisob [31]

The factored form of a - b is \left(5-3 p^{4}\right)\left(25+15 p^{4}+9 p^{8}\right).

<h3>What is monomial factorization ?</h3>

A monomial is an expression that is the product of constant and non-negative integer powers of x, like 3x^{2}..

A monomial is expressed as a product of two or more other monomials when it is factored.

Here,

a = 125

$b=27 p^{12}$

To find: a - b

a - b = 125 - 27 p^{12}$

a - b =  5^{3}-\left(3 p^{4}\right)^{3}$

We know that,

$x^{3}-y^{3}=(x-y)\left(x^{2}+x y+y^{2}\right)$

Finding the factored form of a - b using this method:

$a - b=\left(5-3 p^{4}\right)\left(5^{2}+5\left(3 p^{4}\right)+\left(3 p^{4}\right)^{2}\right)$

$a-b=\left(5-3 p^{4}\right)\left(25+15 p^{4}+9 p^{8}\right)$

So, factored form of a - b is $\left(5-3 p^{4}\right)\left(25+15 p^{4}+9 p^{8}\right)$.

Learn more about monomial factorization here:

brainly.com/question/26278710

#SPJ4

5 0
2 years ago
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