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3 years ago

Can somebody help me?

Mathematics

1 answer:

dusya [7]3 years ago

3 0

A) is the answer ( 3x-y)

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For the following exercises, find (f ∘ g)(x) and (g ∘ f)(x) for each pair of functions.

Rufina [12.5K]

Answer:

The value of $(f \circ g)(x)$ is 17-18x and $(g \circ f)(x)$ is -7-18x.

Step-by-step explanation:

It is given in the question functions f(x) as 3x+2 and g(x)=5-6x.

It is required to find $(f \circ g)(x)$ and $(g \circ f)(x)$ .

To find $(f \circ g)(x)$ , substitute g(x) for x in f(x) and simplify the expression.

To find $(g \circ f)(x)$ , substitute f(x) for x in g(x) and simplify the expression.

Step 1 of 2

Substitute g(x) for x in f(x) and simplify the expression.

$\begin{aligned}&(f \circ g)(x)=f(5-6 x) \\&(f \circ g)(x)=3(5-6 x)+2 \\&(f \circ g)(x)=15-18 x+2 \\&(f \circ g)(x)=17-18 x\end{aligned}$

Step 2 of 2

Substitute f(x) for x in g(x) and simplify the expression.

$\begin{aligned}&(g \circ f)(x)=g(3 x+2) \\&(g \circ f)(x)=5-6(3 x+2) \\&(g \circ f)(x)=5-18 x-12 \\&(g \circ f)(x)=-7-18 x\end{aligned}$

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1 year ago

A recipe for crumb cake says to mix 3/8 cup of brown sugar and 1/3 cup of white sugar. From this sugar mixture, set aside 1/4 cu

ch4aika [34]

brown sugar= $\frac{3}{8}$

white sugar= $\frac{1}{3}$

you need to mix brown sugar with white sugar

$\frac{3}{8}$ + $\frac{1}{3}$ = $\frac{9+8}{24}$ = $\frac{17}{24}$

then it says you need to set aside 1/4 for the crumb topping from the previous sugar mixture that was $\frac{17}{24}$ , so

$\frac{17}{24}$ - $\frac{1}{4}$ = $\frac{68-24}{96}$ = $\frac{11}{24}$

The sugar mixture used to make the cake is $\frac{11}{24}$

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Answer:

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Step-by-step explanation:

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