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GaryK [48]
3 years ago
13

Can somebody help me?

Mathematics
1 answer:
dusya [7]3 years ago
3 0
A) is the answer ( 3x-y)
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Solve the equation. Show your work. 45 = 3b + 69
Cerrena [4.2K]
There should be no problem in finding the value of the unknown variable "b" in the equation given in the question.The equation is solvable for finding the value of "b" because it is the only unknown variable in the single equation that is given in the question.
45 = 3b + 69
Let us reverse both sides of the equation first. then, we get
3b + 69 = 45
3b = 45 - 69
3b = - 24
b = - (24/3)
   = - 8
So from the above deduction, we can easily conclude that the value of b in the given equation is -8.
8 0
3 years ago
Read 2 more answers
James earns $5.15/hour. What equation shows the relationship between his hour wage (g), his weekly wage (w), and hours worked pe
LenKa [72]
5.15 x 3=15.45 /3===5.15
8 0
3 years ago
Read 2 more answers
-2.3,-2 2/4,-2.6 from least to greatest
Pie
If you think about it, you have your answer in your question.

Convert 2/4 to 1/2 which in decimal form, is .5.

You’re final answer is -2.3,-2 2/4,-2.6.

I hope this helps!
7 0
3 years ago
Help easy math question!!!
bogdanovich [222]

Answer:

The length of the third side of the triangle is 30.

Step-by-step explanation:

Here is the formula for the Pythagorean Theorem:

a^{2} + b^{2} = c^{2}

The hypotenuse, based on the problem, is 50. Anyways, let's get back to calculating!

We need to multiply 40 times 40 and 50 times 50.

40 times 40, or 40 squared, equals to 1600.

50 times 50, or 50 squared, equals to 2500.

c^{2} - b^{2}  = a^{2}

Now, let's subtract. 2500 - 1600 = 900. We need to find the square root of 900--which is 30, because 30 times 30, or 30 squared, equals to 900.

8 0
3 years ago
A submarine dives at a constant speed of 10 m/s at a diving angle measured from the vertical
valina [46]

Answer:

155.3 m

Step-by-step explanation:

<u>We have:</u>

θ: is the angle measured from the vertical = 75 °

v = is the speed of the submarine = 10 m/s

t = 1 min

The deep of the front end of the submarine at the end of a 1-minute drive is given by the following ratio:

cos (\theta) = \frac{x}{d}  

<u>Where:</u>

d: is the distance traveled by the submarine in 1 minute

x: is the deep to find

The distance, d, is:

d = v*t = 10 \frac{m}{s}* 1 min * \frac{60 s}{1 min} = 600 m

Now, the deep is:

cos (75) = \frac{x}{600}  

x = cos(75)*600 = 155.3 m

Therefore, the deep of the front end of the submarine at the end of a 1-minute drive is 155.3 m.

I hope it helps you!

3 0
3 years ago
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