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3 years ago

Which function is greater for x < 2 (for all x values less than 2) ?

Mathematics

1 answer:

kodGreya [7K]3 years ago

8 0

Answer:

Function 1

Step-by-step explanation:

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Anyone able to answer this?

Ksivusya [100]

Answer:

B) (4,5)

Step-by-step explanation:

Hope this helps.. (again)

3 0

2 years ago

Read 2 more answers

Use the divergence theorem to calculate the surface integral s f · ds; that is, calculate the flux of f across s. f(x, y, z) = x

valkas [14]

$\mathbf f(x,y,z)=x^4\,\mathbf i-x^3z^2\,\mathbf j+4xy^2z\,\mathbf k$
$\mathrm{div}(\mathbf f)=\dfrac{\partial(x^4)}{\partial x}+\dfrac{\partial(-x^3z^2)}{\partial y}+\dfrac{\partial(4xy^2z)}{\partial z}=4x^3+0+4xy^2=4x(x^2+y^2)$

Let $\mathcal D$ be the region whose boundary is $\mathcal S$ . Then by the divergence theorem,

$\displaystyle\iint_{\mathcal S}\mathbf f\cdot\mathrm d\mathbf S=\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV$

Convert to cylindrical coordinates, setting

$x=r\cos\theta$
$y=r\sin\theta$

and keeping $z$ as is. Then the volume element becomes

$\mathrm dV=r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz$

and the integral is

$\displaystyle\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=0}^{z=r\cos\theta+7}4r\cos\theta\cdot r^2\cdot r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle4\iiint_{\mathcal D}r^4\cos\theta\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\dfrac{2\pi}3$

4 0

4 years ago

Three more than the quotient of a number and 8 is equal to 9

garri49 [273]

Answer:

The number is 48.

Step-by-step explanation:

x/8+3=9

x/8=9-3

x/8=6

x=6*8

x=48

6 0

3 years ago

Slope of (-4, -3) and (14, 0)

rewona [7]

Answer:

slope of (-4,-3)- 0

slope of (14,0)- 2

Step-by-step explanation:

3 0

3 years ago

Their sum is 6 and their difference is 36<br> Help plz

Ivan

Answer:

Step-by-step explanation:

if you can use negative numbers then you could use 21 and -15

adding them together is 21 + (-15) = 6

and then subtracting 21 - (-15) =

21 + 15 = 36

do you think that would work ? :/

3 0

3 years ago

Read 2 more answers