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3 years ago

5

3. What is the slope of a line that passes through (0,-5) and (8,27)?

2 answers:

Elden [556K]3 years ago

6 0

Answer:

4.

Step-by-step explanation:

Slope = difference in y coordinates / difference in the corresponding x coordinates

(27 - (-5)) / (8 - 0)

= 32 / 8

= 4.

Ludmilka [50]3 years ago

4 0

Answer: Well, The entered points belong to an increasing, linear function.

Equation: y = 2.75x + 5.

You're key in this will be y=mx+b right?

Then you're <u>M</u> in y=<u>m</u>x+b is your slope. Therefore, if we take a look at our <u>M</u> in the slope we got,.....<u>y =</u><u> 2.75x</u><u> + 5</u>......it's-

2.75.

So you're slope is<u> y= 2.75x </u>

I'm not that great at explaining but yeah, i tried lolz :3

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What is1/12+7/9. I need help.

Katarina [22]

You have to make them have their least common denominator to add or subtract, in this case 36.
Multiply 1/12 by 3, to get the denominator 36: 3/36.
Multiply 7/9 by 4, to get the denominator 36: 28/36.
Now add the numerators: 3+28=31, 31/36 is as simplified as possible so your answer is 31/36 :) I hope this helps :)

7 0

4 years ago

Step by step what is 2z+7z-z+5

MArishka [77]

///Hope this helps///

3 0

4 years ago

Read 2 more answers

An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of

ANEK [815]

Answer:

(a) 0.152

(b) 0.789

(c) 0.906

Step-by-step explanation:

Let's denote the events as follows:

<em>F</em> = The word free occurs in an email

<em>S</em> = The email is spam

<em>V</em> = The email is valid.

The information provided to us are:

The probability of the word free occurring in a spam message is, $P(F|S)=0.60$
The probability of the word free occurring in a valid message is, $P(F|V)=0.04$
The probability of spam messages is,

$P(S)=0.20$

First let's compute the probability of valid messages:

$P (V) = 1 - P(S)\\=1-0.20\\=0.80$

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

$P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The probability that a message contains the word free is:

$P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\$

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

The probability that a message is spam provided that it contains free is:

$P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\$

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

The probability that a message is valid provided that it does not contain free is:

$P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566$

The probability that a message is valid provided that it does not contain free is approximately 0.906.

4 0

4 years ago

A + b + c = abc(1 + 1 + 1)

Lera25 [3.4K]

If each letter is 1, abc would be equal to 3.

6 0

3 years ago

What Is the answer? <br><img src="https://tex.z-dn.net/?f=6x%20%2B%202%20%2B%206x%20%3C%2014" id="TexFormula1" title="6x + 2 + 6

timofeeve [1]

6x+2+6x<14

add 6x+6x

12x+2<14

subtract 2 from both sides

12x<12

divide by 12

x<1

5 0

3 years ago