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Pavel [41]
3 years ago
5

I need help with this please

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
5 0
D since it looks pretty difficult
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800 grams equals how many pounds?
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3 years ago
A random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample stand
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Answer:

We conclude that the population mean is different from 10.5.

Step-by-step explanation:

We are given that a random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample standard deviation is 2.

<em>We have to test the claim that the population mean is 10.5.</em>

Let, NULL HYPOTHESIS, H_0 : \mu = 10.5  {means that the population mean is 10.5}

ALTERNATE HYPOTHESIS, H_a : \mu \neq 10.5  {means that the population mean is different from 10.5}

The test statistics that will be used here is One-sample t-test;

           T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean = 11

            s = sample standard deviation = 2

            \mu = population mean

            n = sample of values = 16

So, <u>test statistics</u> =  \frac{11-10.5}{\frac{2}{\sqrt{16} } } ~ t_1_5

                            = 1

<em>Now, at 0.05 significance level, t table gives a critical value of 2.131 at 15 degree of freedom. Since our test statistics is way less than the critical value of t so we have insufficient evidence to reject null hypothesis as it will not fall in the rejection region.</em>

Therefore, we conclude that the population mean is different from 10.5.

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