Find the area of a circle with radius, r = 7.49m. Give your answer rounded to 2 DP.

Mathematics

1 answer:

adell [148]2 years ago

7 0

Answer:

Area ≈ 176.24m²

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P is the set of natural numbers<br> less than 6.

Wewaii [24]

Answer:

Therefore,

P = { 1 , 2 , 3 , 4 , 5 }

Step-by-step explanation:

Natural numbers:

Natural numbers are those numbers starting from 1 , 2 , 3 , 4 ,......... and so on.

Also it is denoted by 'N'.

Zero does not include a natural number.

Therefore the set of natural numbers less than 6 is 1 , 2 , 3 , 4 , and 5.

Here in the question it is given that

P is the set of natural numbers

less than 6.

∴ P = { 1 , 2 , 3 , 4 , 5 }

6 0

3 years ago

a spherical balloon is deflated at a rate of 256pi/3 cm^3/sec. at what rate is the radius of the balloon changing when the radiu

Hunter-Best [27]

What you need to look for is $\frac { dr }{ dt }$ when r=8.

Now:

$Volume\quad of\quad a\quad sphere:\\ \\ V=\frac { 4 }{ 3 } \pi { r }^{ 3 }$

$\therefore \quad \frac { dV }{ dr } =\frac { 4 }{ 3 } \pi \cdot 3{ r }^{ 2 }=4\pi { r }^{ 2 }\\ \\ \therefore \quad \frac { dr }{ dV } =\frac { 1 }{ \frac { dV }{ dr } } =\frac { 1 }{ 4\pi { r }^{ 2 } }$

$And:\\ \\ \frac { dV }{ dt } =-\frac { 256\pi }{ 3 } \\ \\ Therefore:\\ \\ \frac { dr }{ dt } =\frac { dr }{ dV } \cdot \frac { dV }{ dt }$

$\\ \\ =\frac { 1 }{ 4\pi { r }^{ 2 } } \cdot -\frac { 256\pi }{ 3 } \\ \\ =-\frac { 256 }{ 12 } \cdot \frac { \pi }{ \pi } \cdot \frac { 1 }{ { r }^{ 2 } }$

$\\ \\ =-\frac { 64 }{ 3{ r }^{ 2 } } \\ \\ When\quad r=8,\\ \\ \frac { dr }{ dt } =-\frac { 64 }{ 3\cdot { 8 }^{ 2 } } =-\frac { 1 }{ 3 } \\ \\ Answer:\quad -\frac { 1 }{ 3 } \quad cm/sec$

3 0

3 years ago

Can you solve this equation?

Leya [2.2K]

Answer:

$10 + 10 + 10 = 30 \\ 10 + 5 + 5 = 20 \\ 5 + 4 + 4 = 13 \\ 10 + 5 + 2 = 17$