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notsponge [240]
3 years ago
13

In the expression 2 to the 4th power, 4 is called the

Mathematics
1 answer:
LenKa [72]3 years ago
4 0

Answer:

exponent

Step-by-step explanation:

In 2^4, 4 is the "exponent."

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Drug x, a drug that claims to treat male pattern scalp hair loss, was administered for 12 months to over 1800 men aged 18 to 41
egoroff_w [7]

The following statement

'In general, men who took drug x maintained or increased the number of visible scalp hairs; while scalp hairs counts in men who took the placebo continued to decrease'

can be referred as descriptive statistics, since we are saying that the msot of the men who took the drug gain scalp hairs while the contrary happened from those men who took placebo.

On the other hand, the statement

'drug x is effective in maintaining or increasing the amount of scalp hair in men'

Is a deduction you make, so it can be referred as inferential statistics

5 0
3 years ago
Two numbers total 63 and have a difference of 31. Find the two numbers
Anastaziya [24]

Answer: 47 and 16

Step-by-step explanation:

- Make Two Equations

x + y = 63

x - y = 31

- Set one of the equations equal to one of the variables

x + y = 63

x = 31 + y

- Substitute the equation back into the other one

(31 + y) + y = 63

31 + 2y = 63

2y = 32

y = 16

- Substitute the answer back into the equation

x + y = 63

x + 16 = 63

x = 47

5 0
3 years ago
Read 2 more answers
Three-quarters of a number is. 15 work out four-fifths of the number.
Wittaler [7]

3/4 of X = 15

Multiplying out gives;

3X = 4x15

3X= 60

X = 20

Therefore, 4/5 of 20

Putting X = 20 we have;

4/5 x 20 = 16

so the answer is 16

3 0
3 years ago
Read 2 more answers
For each value of 1 ≤ n ≤ 100, the highest common factor of 8n + 3 and 5n + 4 is written down. What is the sum of these values
DerKrebs [107]

Let gcd(8n + 3, 5n + 4) = d

⟹d|8n+3∧d|5n+4

⟹d|8(5n+4)−5(8n+3)

⟹d|17

Therefore highest common factor of 8n + 3 and 5n + 4 is either 1 or 17 for all n

learn more of gcd here brainly.com/question/25550841

#SPJ9

6 0
2 years ago
A researcher tests the braking distances of several cars. The braking distance from 60 miles per hour to a complete stop on dry
ZanzabumX [31]

Answer:

The longest braking distance one of these cars could have and still be in the bottom 1% is of 116.94 feet.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The braking distances of a sample of cars are normally distributed, with a mean of 129 feet and a standard deviation of 5.18 feet.

This means that \mu = 129, \sigma = 5.18

What is the longest braking distance one of these cars could have and still be in the bottom 1%?

This is the 1st percentile, which is X when Z has a pvalue of 0.01, so X when Z = -2.327.

Z = \frac{X - \mu}{\sigma}

-2.327 = \frac{X - 129}{5.18}

X - 129 = -2.327*5.18

X = 116.94

The longest braking distance one of these cars could have and still be in the bottom 1% is of 116.94 feet.

5 0
3 years ago
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