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3 years ago

F(x) = -x + 5, what is the value of f(-4)? I

Mathematics

2 answers:

liberstina [14]3 years ago

7 0

Answer:

Step-by-step explanation:

F(x)=-x+5

f(-4)= -(-4)+5

f(-4)= 4+5

f(-4)= 8

Only we have to substitute value of x then after simplification we will get answer..Hope this will help

hjlf3 years ago

4 0

So..

All we have to do is think of something for (X) a simple replacement.

(THis took me a bit long to understand the Question)

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Please can someone help I try it hard but I don’t understand it

sammy [17]

He could have scored 7, 14, 21, 28, 35, or 42 points (all multiples of 7 less than 45).

answer: B

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3 years ago

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Nicole has 83 erasers. Susan gives Nicole 5 more. Later, Nicole buys 13 oranges at the store. How many erasers does Nicole have

zheka24 [161]

Answer: Nicole has 88 erasers in all

Step-by-step explanation:

Number of erasers that Nicole has = 83

Number of erasers given to Nicole= 5

Total number of erasers Nicole has in all = 83+5= 88 erasers

Therefore Nicole has 88 erasers.

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3 years ago

For each ordered pair, determine whether it is a solution to the system of equations.

-Dominant- [34]

The only ordered pair that is a solution to the given system of equations is (-2, -6)

<h3>System of Linear Equations </h3>

From the question, we are to determine if each ordered pair is a solution to the given system of equations

The given system of equations is

-9x + 2y = 6

5x - 3y = 8

For (7, 9)

That is,

x = 7, y = 9

Putting the values into the first equation

Is -9(7) + 2(9) = 6

-63 + 18 = 6

-45 ≠ 6

Thus, (7,9) is not a solution

For (0, 3)

That is,

x = 0, y = 3

Putting the values into the first equation

Is -9(0) + 2(3) = 6

0 + 6 = 6

6 = 6

The ordered pair satisfies the first equation

Testing for the second equation

Is 5(0) - 3(3) = 8

0 - 9 = 8

-9 ≠ 8

Thus, (0, 3) is not a solution

For (5, -4)

That is,

x = 5, y = -4

Putting the values into the first equation

Is -9(5) + 2(-4) = 6

-45 - 8 = 6

-53 ≠ 6

Thus, (-5,4) is not a solution

For (-2, -6)

That is,

x = -2, y = -6

Putting the values into the first equation

Is -9(-2) + 2(-6) = 6

18 - 12 = 6

6 = 6

The ordered pair satisfies the first equation

Testing for the second equation

Is 5(-2) -3(-6) = 8

-10 + 18 = 8

8 = 8

The ordered pair satisfies the second equation

∴ The ordered pair that is a solution to the system of equations is (-2, -6)

Hence, the only ordered pair that is a solution to the given system of equations is (-2, -6)

Learn more on System of equations here: brainly.com/question/8630769

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1 year ago

Let $f(x) = x^2$ and $g(x) = \sqrt{x}$. Find the area bounded by $f(x)$ and $g(x).$

Anna [14]

Answer:

$\large\boxed{1\dfrac{1}{3}\ u^2}$

Step-by-step explanation:

Let's sketch graphs of functions f(x) and g(x) on one coordinate system (attachment).

Let's calculate the common points:

$x^2=\sqrt{x}\qquad\text{square of both sides}\\\\(x^2)^2=\left(\sqrt{x}\right)^2\\\\x^4=x\qquad\text{subtract}\ x\ \text{from both sides}\\\\x^4-x=0\qquad\text{distribute}\\\\x(x^3-1)=0\iff x=0\ \vee\ x^3-1=0\\\\x^3-1=0\qquad\text{add 1 to both sides}\\\\x^3=1\to x=\sqrt[3]1\to x=1$

The area to be calculated is the area in the interval [0, 1] bounded by the graph g(x) and the axis x minus the area bounded by the graph f(x) and the axis x.

We have integrals:

$\int\limits_{0}^1(\sqrt{x})dx-\int\limits_{0}^1(x^2)dx=(*)\\\\\int(\sqrt{x})dx=\int\left(x^\frac{1}{2}\right)dx=\dfrac{2}{3}x^\frac{3}{2}=\dfrac{2x\sqrt{x}}{3}\\\\\int(x^2)dx=\dfrac{1}{3}x^3\\\\(*)=\left(\dfrac{2x\sqrt{x}}{2}\right]^1_0-\left(\dfrac{1}{3}x^3\right]^1_0=\dfrac{2(1)\sqrt{1}}{2}-\dfrac{2(0)\sqrt{0}}{2}-\left(\dfrac{1}{3}(1)^3-\dfrac{1}{3}(0)^3\right)\\\\=\dfrac{2(1)(1)}{2}-\dfrac{2(0)(0)}{2}-\dfrac{1}{3}(1)}+\dfrac{1}{3}(0)=2-0-\dfrac{1}{3}+0=1\dfrac{1}{3}$

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