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a_sh-v [17]
3 years ago
6

A bus start from rest and then moves with a constant acceleration of 2m/s square. calculate its time of traven if its final velo

city is 20 m/s​
Physics
1 answer:
pshichka [43]3 years ago
5 0

Answer:

Its Answer is 10 s.

Explanation:

As acceleration is defined as time rate of change of velocity. So,

a =  ( vf - vi ) ÷ t

2 = (20 - 0 ) ÷ t

2 =  20 ÷  t

t = 20 ÷ 2

t  = 10 s

We have put initial velocity as zero because  body is starting from rest.

<em>Hope it helps.</em>

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A 6.5 kg rock thrown down from a 120m high cliff with initial velocity 18 m/s down. Calculate
Olegator [25]

Answer:

See the answers below.

Explanation:

In order to solve this problem we must use the principle of energy conservation. Which tells us that the energy of a body will always be the same regardless of where it is located. For this case we have two points, point A and point B. Point A is located at the top at 120 [m] and point B is in the middle of the cliff at 60 [m].

E_{A}=E_{B}

The important thing about this problem is to identify the types of energy at each point. Let's take the reference level of potential energy at a height of zero meters. That is, at this point the potential energy is zero.

So at point A we have potential energy and since a velocity of 18 [m/s] is printed, we additionally have kinetic energy.

E_{A}=E_{pot}+E_{kin}\\E_{A}=m*g*h+\frac{1}{2}*m*v^{2}

At Point B the rock is still moving downward, therefore we have kinetic energy and since it is 60 [m] with respect to the reference level we have potential energy.

E_{B}=m*g*h+\frac{1}{2}*m*v^{2}

Therefore we will have the following equation:

(6.5*9.81*120)+(0.5*6.5*18^{2} )=(6.5*9.81*60)+(0.5*6.5*v_{B}^{2} )\\3.25*v_{B}^{2} =4878.9\\v_{B}=\sqrt{1501.2}\\v_{B}=38.75[m/s]

The kinetic energy can be easily calculated by means of the kinetic energy equation.

KE_{B}=\frac{1}{2} *m*v_{B}^{2}\\KE_{B}=0.5*6.5*(38.75)^{2}\\KE_{B}=4878.9[J]

In order to calculate the velocity at the bottom of the cliff where the reference level of potential energy (potential energy equal to zero) is located, we must pose the same equation, with the exception that at the new point there is only kinetic energy.

E_{A}=E_{C}\\6.5*9.81*120+(0.5*9.81*18^{2} )=0.5*6.5*v_{C}^{2} \\v_{c}^{2} =\sqrt{2843.39}\\v_{c}=53.32[m/s]

5 0
3 years ago
The head of a rattlesnake can accelerate at 49 m/s2 in striking a victim. If a car could do as well, how long would it take to r
Anettt [7]
<h2>Time taken is 0.459 seconds</h2>

Explanation:

We have equation of motion v = u + at

     Initial velocity, u = 0 m/s

     Final velocity, v = 81 km/hr = 22.5 m/s    

     Time, t = ?

     Acceleration, a = 49 m/s²

     Substituting

                      v = u + at  

                      22.5 = 0 + 49 x t

                      t = 0.459 seconds

   Time taken is 0.459 seconds

3 0
4 years ago
A train travels 70 kilometers in 1 hours, and then 63 kilometers in 2 hours. What is its average speed?
lozanna [386]
The answer is:  " 44 \frac{1}{3} km " ; 
                              or; write as:  " 44.333 km " .
___________________________________________________________
Explanation:
___________________________________________________________
(70 km + 63 km) ÷ (2 + 1 ) =  133 km ÷ 3 =  " 44 \frac{1}{3} km "  ; 
                                                                            or; write as:  " 44.333 km " .
___________________________________________________________
3 0
4 years ago
A 2-kg book falls off a shelf. it hits a student traveling 2 m/s. how much kinetic energy does the book have?
jekas [21]
Kinetic energy = 1/2 * m * V^2

K = 1/2 * 2kg * 4
5 0
3 years ago
What type of tool would best be used to map a section of the ocean floor?
qwelly [4]

Echo sounding is the key method scientists use to map,uses sound waves bounced off the ocean bottom.

3 0
3 years ago
Read 2 more answers
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