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hjlf
3 years ago
12

Find the value of x.

Mathematics
1 answer:
dexar [7]3 years ago
3 0
180 JAJAJAJAJAJAJAJAJAJAJAJA
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The interquartile range (IQR) for the<br>data:<br>32,7,3,-5,1,8<br>, 10,36 is :​
GenaCL600 [577]

Answer:

<em>Your Interquartile range (IQR) would be 19.</em>

Step-by-step explanation:

-5, 1, 3, 7, 8, 10, 32, 36

Median: 7.5

Lower quartile: 2

Upper quartile: 21

Interquartile range: 21 - 2 = 19

7 0
3 years ago
Which number is the median? 5, 15, 16, 20, 21, 21, 23, 23, 23, 26, 26, 26, 26, 27, 27, 29, 29, 29, 29, 29, 30, 30, 30, 30
scoray [572]

Answer:

median is 26

Step-by-step explanation:

26+26=52

52÷2=26

8 0
3 years ago
Read 2 more answers
Write a rule for each sequence. Find the next three terms.<br><br> 8,14,20,26
anastassius [24]
Aruthmetic sequene is
an=a1+(n-1)d
where d=common difference between terms
adds 6 every time
d=6
first term is 8
a1=8
8+6(n-1)
distribute
8+6n-6
8-6+6n
2+6n is answer
8 0
3 years ago
What is the completely factored form of d4 -8d2 + 16
irinina [24]
According to Vieta's Formulas, if x_1,x_2 are solutions of a given quadratic equation:

ax^2+bx+c=0

Then:

a(x-x_1)(x-x_2) is the completely factored form of ax^2+bx+c.

If choose x=d^2, then:

\displaystyle x^2-8x+16=0\\\\x_{1,2}= \frac{8\pm  \sqrt{64-64} }{2}=4

So, according to Vieta's formula, we can get:

x^2-8x+16=(x-4)(x-4)= (x-4)^2

But x=d^2:

d^4-8d^2+16=(d^2-4)^2=[(d+2)(d-2)]^2=(d+2)^2(d-2)^2
8 0
3 years ago
What are all values of x that satisfy 4x-1 &lt; 6x+9
Lady bird [3.3K]

The values of x that makes the inequality true are all values less than -5

<h3>Inequality expressions</h3>

Given the inequalities below expressed as;

4x-1 < 6x+9

Collect the like terms

4x-6x < 9+1

-2x < 10

x <-10/2

<h3>x < -5</h3>

Hence the values of x that makes the inequality true are all values less than -5

Learn more on inequality here; brainly.com/question/24372553

#SPJ1

3 0
2 years ago
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