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2 years ago

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Starting from the entrance of her school, Alyssa walked 400 feet due north, then 300 feet due east, and ended up at the entrance

of a running track. Miki walked directly from the entrance of the school to the entrance of the running track. How many more feet did Alyssa walk than Miki?

1 answer:

Jobisdone [24]2 years ago

6 0

Answer:

Alyssa walked 200 ft more than Miki.

Step-by-step explanation:

According to the Pythagorean theorem formula if we square the a(400) and b(300) and add them both we would get 250,000. From then you square root it to 500. So Miki walked 500ft and Alyssa walked 700ft (400+300). Subtract 500 from 700 and you would get 200ft.

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For each level of precision, find the required sample size to estimate the mean starting salary for a new CPA with 95 percent co

Rzqust [24]

Answer:

(a) Margin of error ( E) = $2,000 , n = 54

(b) Margin of error ( E) = $1,000 , n = 216

(c) Margin of error ( E) = $500 , n= 864

Step-by-step explanation:

Given -

Standard deviation $\sigma$ = $7,500

$\alpha$ = 1 - confidence interval = 1 - .95 = .05

$Z_{\frac{\alpha}{2}}$ = $Z_{\frac{.05}{2}}$ = 1.96

let sample size is n

(a) Margin of error ( E) = $2,000

Margin of error ( E) = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

E = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$E^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{2000^{2}} \times 7500^{2}$

n = 54.0225

n = 54 ( approximately)

(b) Margin of error ( E) = $1,000

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

1000 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$1000^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{1000^{2}} \times 7500^{2}$

n = 216

(c) Margin of error ( E) = $500

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

500 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$500^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{500^{2}} \times 7500^{2}$

n = 864

7 0

3 years ago

Use the distributive property to solve the following 4(4a+6b)

Alina [70]

$4(4a+6b) =16a+24b$

6 0

2 years ago

A company that makes nails finds that it would sell 42 boxes of nails per month if they are priced at $20 per box. If the compan

denpristay [2]

The answer is D.

If x = number of boxes sold and y = price of nails box, then it is best represented by the equation y = 62 - x.
Checking:
If y = 20 and x = 42,
20 = 62 - 42
20 = 20

If y = 10 and x = 52.
10 = 62 - 52
10 = 10

<span>Thank you for posting your question. I hope you found you were after. </span><span>Please feel free to ask me another.</span>

8 0

3 years ago

sasho [114]

Answer:

-40

-6

51

Step-by-step explanation:

-33+-7 you are adding two negatives

9+(-15) you are adding a negative to a positive which gets you closer to zero

5-(-46) you are subtracting a negative which is adding

7 0

2 years ago

ROOTS AND CUBES<br> Can someone please help me answer all 4 following?

Alex Ar [27]

NOTES:

squared (²) means multiply that number by itself 2 times
cubed (³) means multiply that number by itself 3 times
square root (√) means 2 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
cubed root (∛) means 3 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical

Answer: (C) 41

<u>Step-by-step explanation:</u>

$\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41$

***************************************************************************************

Answer: (C) 10

<u>Step-by-step explanation:</u>

$\bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}$

$=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}$

$=\bigg(\dfrac{7}{3}\times3-2\bigg)\times \dfrac{1}{5}+9$

$=(7 - 2)\times \dfrac{1}{5}+9$

$=5 \times \dfrac{1}{5}+ 9$

$= 1 + 9$

$= 10$

***************************************************************************************

8² = 8 · 8 = 64 11² = 11 · 11 = 121

5³ = 5 · 5 · 5 = 125 3³ = 3 · 3 · 3 = 27

$\sqrt{1600}=\sqrt{40\cdot 40}=40$ $\sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4$

$\sqrt{144}=\sqrt{12\cdot 12}=12$ $\sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20$

3 0

2 years ago