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telo118 [61]
3 years ago
6

Starting from the entrance of her school, Alyssa walked 400 feet due north, then 300 feet due east, and ended up at the entrance

of a running track. Miki walked directly from the entrance of the school to the entrance of the running track. How many more feet did Alyssa walk than Miki?
Mathematics
1 answer:
Jobisdone [24]3 years ago
6 0

Answer:

Alyssa walked 200 ft more than Miki.

Step-by-step explanation:

According to the Pythagorean theorem formula if we square the a(400) and b(300) and add them both we would get 250,000. From then you square root it to 500. So Miki walked 500ft and Alyssa walked 700ft (400+300). Subtract 500 from 700 and you would get 200ft.

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Write the linear equation that gives the rule for this table.
MAVERICK [17]

Answer:

The linear equation that gives the rule for this table will be:

  • y=x+25

Step-by-step explanation:

Taking two points from the table

  • (2, 27)
  • (3, 28)

Finding the slope between two points

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(2,\:27\right),\:\left(x_2,\:y_2\right)=\left(3,\:28\right)

m=\frac{28-27}{3-2}

m=1

We know the slope-intercept form of linear equation is

y=mx+b

where m is the slope and b is the y-intercept

substituting the point (2, 27) and m=1 in the slope-intercept form to determine the y-intercept 'b'

y=mx+b

27 = 1(2)+b

27-2 = b

b = 25

Now, substituting m=1 and b=25 in the slope-intercept form to determine the linear equation

y=mx+b

y=1(x)+25

y=x+25

Thus, the linear equation that gives the rule for this table will be:

  • y=x+25
4 0
3 years ago
HELP PLEASE FAST<br> Solve for c. −18c=2 What is the answer? −16 −4 4 16
denpristay [2]
To solve for c, you divide both sides by -18. If you do that, your answer will be -1/16. So, I think you typed the question wrong. Pretty sure it's the first option.
8 0
4 years ago
Read 2 more answers
Find the vertex point, axis of symmetry, x-intercepts, and y-intercept of the
Bond [772]

Answer:

1) Vertex point (-1.5,-20.25)

2) axis of symmetry: x=-1.5

3) x-intercepts: (-6,0) and (3,0)

4) y-intercept: (0,18)

5) Graph in attachment.

Step-by-step explanation:

1) The given parabola has equation:

y =  {x}^{2}  + 3x - 18

We need to complete the square.

y =  {x}^{2}  + 3x + {1.5}^{2}   -  {1.5}^{2} - 18

y = ( {x + 1.5)}^{2}  - 20. 25

This function is in the vertex form:

y = a( {x - h)}^{2}  + k

where (h,k) is the vertex, x=h is the axis of symmetry.

By comparing our equation to the general vertex form:

The vertex point is (-1.5,-20.25)

2) The axis of symmetry divides the parabola into two congruent halves.

Since this is a vertical parabola, the axis of symmetry occuring at x=h is a vertical line.

The axis of symmetry is x=-1.5

3) Y-INTERCEPT.

The y-intercept is the point where the graph cross the y-axis.

At this point, the value of x is zero.

To find the y-intercept, we substitute x=0 in the equation of the parabola and simplify.

when x=0,

y =  {(0)}^{2}  + 3(0) - 18 =  - 18

The y-intercept is (0,-18).

4) X-INTERCEPT

The x-intercepts are the points where the graph touches or intersect the x-axis.

To find the x-intercept, we substitute y=0.

( {x + 1.5)}^{2}  - 20.25 = 0

Add 20.25 to both sides;

( {x + 1.5)}^{2}   =  20.25

Take square root.

(x + 1.5)=  \pm \sqrt{20.25}

x =   - 1.5\pm 4.5

x =   - 1.5 -  4.5 \:  \:  or \:  \: x =  - 1.5 + 4.5

x =  - 6 \: or \: x = 3

The x-intercepts are(-6,0) and (3,0).

4) GRAPH

To graph this function, we can use transformation.

To graph the function,

y =  {(x + 1.5)}^{2}  - 20.25

We shift the parent quadratic function 1.5 units left and 20.25 units down.

See attachment for graph.

5 0
3 years ago
Given that 'n' is a natural number. Prove that the equation below is true using mathematical induction.
LenaWriter [7]

<h3>To ProvE :- </h3>

  • 1 + 3 + 5 + ..... + (2n - 1) = n²

<u>Method</u><u> </u><u>:</u><u>-</u>

If P(n) is a statement such that ,

  1. P(n) is true for n = 1
  2. P(n) is true for n = k + 1 , when it's true for n = k ( k is a natural number ) , then the statement is true for all natural numbers .

\sf\to \textsf{ Let P(n) :  1 + 3 + 5 + $\dots$ +(2n-1) = n$^{\sf 2}$ }

Step 1 : <u>Put </u><u>n </u><u>=</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\longrightarrow LHS = \boxed{\sf 1 } \\

\sf\longrightarrow RHS = n^2 = 1^2 = \boxed{\sf 1 }

Step 2 : <u>Assume </u><u>that </u><u>P(</u><u>n)</u><u> </u><u>is </u><u>true </u><u>for </u><u>n </u><u>=</u><u> </u><u>k </u><u>:</u><u>-</u>

\sf\longrightarrow 1 + 3 + 5 + \dots + (2k - 1 ) = k^2

  • Add (2k +1) to both sides .

\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+(2k+1)=k^2+(2k+1)

  • RHS is in the form of ( a + b)² = a²+b²+2ab .

\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+(2k+1)= (k +1)^2

  • Adding and subtracting 1 to LHS .

\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+(2k+1) + 1 -1  = (k +1)^2 \\

\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+(2k+2) - 1 = (k +1)^2

  • Take out 2 as common .

\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+\{2(k+1)-1\}= (k +1)^2

  • P(n) is true for n = k + 1 .

Hence by the principal of Mathematical Induction we can say that P(n) is true for all natural numbers 'n' .

<em>*</em><em>*</em><em>Edits</em><em> are</em><em> welcomed</em><em>*</em><em>*</em>

8 0
2 years ago
Read 2 more answers
Two cars, 129 miles apart, start moving towards each other at the same time. one is moving 3 times as fast as the other. if they
Nata [24]

x – slower car

3x faster car

D = distance traveled by slower car

D = distance traveled by faster car

D+d = 129

Both cars traveled for 2 hours

D=2x

d=2(3x) = 6x

2x+6x = 129

8x = 129

x=129/8 = 16.125 miles per hour


5 0
3 years ago
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