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2 years ago

$12.95 for 3 pounds of nuts or $21.45 for 5 pounds of nuts

Mathematics

1 answer:

Zarrin [17]2 years ago

8 0

First, find the base rate of both of the numerals, to do this simply divide the price by the number of units.

12.95 divided by 3 is 4.32 ( rounded to nearest cent )

21.45 divided by 5 is 4.29 ( rounded to nearest cent )

So, if you want the better deal ( which is what I've interpreted ), then 5 pounds of nuts is the better deal BY 3 cents.

Hope this helps, if not, comment below please!!!!

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WITCHER [35]

Answer:

It depends on what shape you have. Here are some formulas for different shapes.

Step-by-step explanation:

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I hope this helps!

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2 years ago

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2 years ago

Solve for x round your answer to the nearest tenth

serious [3.7K]

Answer:

13.7

Step-by-step explanation:

Pythagorean theorem converse

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2 years ago

Read 2 more answers

Please help quick will give brainliest!

Karo-lina-s [1.5K]

Answer:

The statement that correctly uses limits to determine the end behavior of f(x) is;

$\lim\limits_{x \to \pm \infty} \dfrac{7 \cdot x^2+ x + 1}{x^4 + 1}= \lim\limits_{x \to \pm \infty} \dfrac{7 }{x^2 }$ so the end behavior of the function is that as x → ±∞, f(x) → 0

Step-by-step explanation:

The given function is presented here as follows;

$f(x) = \dfrac{7 \cdot x^2+ x + 1}{x^4 + 1}$

The limit of the function is presented as follows;

$\lim\limits_{x \to \pm \infty} \dfrac{7 \cdot x^2+ x + 1}{x^4 + 1}$

Dividing the terms by x², we have;

$\lim\limits_{x \to \pm \infty} \dfrac{\dfrac{7 \cdot x^2}{x^2} + \dfrac{x}{x^2} + \dfrac{1}{x^2} }{\dfrac{x^4}{x^2} +\dfrac{1}{x^2} }= \lim\limits_{x \to \pm \infty} \dfrac{7 + \dfrac{1}{x} + \dfrac{1}{x^2} }{x^2 +\dfrac{1}{x^2} }$

As 'x' tends to ±∞, we have;

$\lim\limits_{x \to \pm \infty} \dfrac{7 + \dfrac{1}{x} + \dfrac{1}{x^2} }{x^2 +\dfrac{1}{x^2} } = \lim\limits_{x \to \pm \infty} \dfrac{7 + 0 + 0 }{x^2 +0 } = \lim\limits_{x \to \pm \infty} \dfrac{7 }{x^2 }$

However, we have that the end behavior of 7/x² as 'x' tends to ±∞ is 7/x² tends to 0;

Therefore, we have;

$f(x) \rightarrow 0 \ as \lim\limits_{x \to \pm \infty} \dfrac{7 }{x^2 }$

The statement that correctly uses limits to determine the end behavior of f(x) is therefor given as follows;

$\lim\limits_{x \to \pm \infty} \dfrac{7 \cdot x^2+ x + 1}{x^4 + 1}= \lim\limits_{x \to \pm \infty} \dfrac{7 }{x^2 }$ so the end behavior of the function is that as x → ±∞, f(x) → 0.

8 0

2 years ago

The area and the ratio of the length to the width of a rectangle are given. Find the length and width of the rectangle. Area: 29

Dahasolnce [82]

Answer:

Step-by-step explanation:

L = 3x

w = 2x

Area = 294 ft^2

Formula

Area = L * w

Solution

Area = L * w Substitute into formula

294 - 3x * 2x Combine the right and switch

6x^2 = 294 Divide by 6

x^2 = 294/6

x^2 = 49 Take the square root of both sides

√x^2 = √49

x = 7

w = 2*7 = 2x = 14

L = 3*7 = 3x =21

8 0

1 year ago