Evaluate the function F(x)=3x^2+5x-14

How do you determine where f(x)=cos^(-1)(lnx) is continuous?

olga nikolaevna [1]

$\ln x$ is continuous over its domain, all real $x>0$ .

Meanwhile, $\cos^{-1}y$ is defined for real $-1\le y\le1$ .

If $y=\ln x$ , then we have $-1\le \ln x\le1\implies \dfrac1e\le x\le e$ as the domain of $\cos^{-1}(\ln x)$ .

We know that if $f$ and $g$ are continuous functions, then so is the composite function $f\circ g$ .

Both $\cos^{-1}y$ and $\ln x$ are continuous on their domains (excluding the endpoints in the case of $\cos^{-1}y$ ), which means $\cos^{-1}(\ln x)$ is continuous over $\dfrac1e$ .

7 0

3 years ago

A student carried out an experiment to determine the amount of vitamin C in a tablet sample. He performed 5 trials to produce th

ivolga24 [154]

Answer:

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

P-value = 0.166.

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{5}(490+502+505+495+492)\\\\\\M=\dfrac{2484}{5}\\\\\\M=496.8\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}((490-496.8)^2+(502-496.8)^2+(505-496.8)^2+(495-496.8)^2+(492-496.8)^2)}\\\\\\s=\sqrt{\dfrac{166.8}{4}}\\\\\\s=\sqrt{41.7}=6.5\\\\\\$

Then, we can perform the hypothesis t-test for the mean.

The claim is that the amount of vitamin C in a tablet sample is different from 500 mg.

Then, the null and alternative hypothesis are:

$H_0: \mu=500\\\\H_a:\mu< 500$

The significance level is 0.05.

The sample has a size n=5.

The sample mean is M=496.8.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.5.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{6.5}{\sqrt{5}}=2.907$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{496.8-500}{2.907}=\dfrac{-3.2}{2.907}=-1.1$

The degrees of freedom for this sample size are:

$df=n-1=5-1=4$

This test is a left-tailed test, with 4 degrees of freedom and t=-1.1, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=P(t$

As the P-value (0.166) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

4 0

3 years ago

Help?

Gre4nikov [31]

A = P(1 + r)^t is the interest formula
A = 1000(1 + .02)^t
A = 1000(1.02)^t
I'm not sure which of your two answers A or C have the t raised to a power but you need to choose the one with the t raised to a power.

6 0

3 years ago

Which side lengths form a right triangle? Choose all answers that apply: Choose all answers that apply: (Choice A) A 3, 6, \sqrt

dlinn [17]

Answer:

A, B and C

Step-by-step explanation:

Given any three side lengths of a right triangle, the longest side is the hypotenuse.

The side lengths of a right triangle must satisfy the Pythagorean Theorem.

Pythagorean Theorem: $Hypotenuse^2=Opposite^2+Adjacent^2$