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2 years ago

Presenting someone else's words or ideas as your own is:

Mathematics

2 answers:

mote1985 [20]2 years ago

7 0

Answer:

<em>B. plagiarizing</em>

Step-by-step explanation:

...........

Mumz [18]2 years ago

6 0

B plagiarizing because it means to copy someone.

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3y²z(2y²z + 4yz - y + z) = <br> 6y⁴z² + 12y³z² - 3y³z + 3y²z

lord [1]

18y⁸z²=18y⁸z², you have to simplify it and add like terms to get your answer

3 0

3 years ago

Consider a discrete random variable x with pmf px (1) = c 3 ; px (2) = c 6 ; px (5) = c 3 and 0 otherwise, where c is a positive

PtichkaEL [24]

Looks like the PMF is supposed to be

$\mathbb P(X=x)=\begin{cases}\dfrac c3&\text{for }x\in\{1,5\}\\\\\dfrac c6&\text{for }x=2\\\\0&\text{otherwise}\end{cases}$

which is kinda weird, but it's not entirely clear what you meant...

Anyway, assuming the PMF above, for this to be a valid PMF, we need the probabilities of all events to sum to 1:

$\displaystyle\sum_{x\in\{1,2,5\}}\mathbb P(X=x)=\dfrac c3+\dfrac c6+\dfrac c3=\dfrac{5c}6=1\implies c=\dfrac65$

Next,

$\mathbb P(X>2)=\mathbb P(X=5)=\dfrac c3=\dfrac25$

$\mathbb E(X)=\displaystyle\sum_{x\in\{1,2,5\}}x\,\mathbb P(X=x)=\dfrac c3+\dfrac{2c}6+\dfrac{5c}3=\dfrac{7c}3=\dfrac{14}5$

$\mathbb V(X)=\mathbb E\bigg((X-\mathbb E(X))^2\bigg)=\mathbb E(X^2)-\mathbb E(X)^2$
$\mathbb E(X^2)=\displaystyle\sum_{x\in\{1,2,5\}}x^2\,\mathbb P(X=x)=\dfrac c3+\dfrac{4c}6+\dfrac{25c}3=\dfrac{28c}3=\dfrac{56}5$
$\implies\mathbb V(X)=\dfrac{56}5-\left(\dfrac{14}5\right)^2=\dfrac{84}{25}$

If $Y=X^2+1$ , then $X^2=Y-1\implies X=\sqrt{Y-1}$ , where we take the positive root because we know $X$ can only take on positive values, namely 1, 2, and 5. Correspondingly, we know that $Y$ can take on the values $1^2+1=2$ , $2^2+1=5$ , and $5^2+1=26$ . At these values of $Y$ , we would have the same probability as we did for the respective value of $X$ . That is,

$\mathbb P(Y=y)=\begin{cases}\dfrac c3&\text{for }y=2\\\\\dfrac c6&\text{for }y=5\\\\\dfrac c3&\text{for }y=26\\\\0&\text{otherwise}\end{cases}$

Part (5) is incomplete, so I'll stop here.

8 0

3 years ago

Help I need help A B C or D

Luda [366]

B It’s the one that makes sense

4 0

2 years ago

How can I understand derivation better?

Dafna11 [192]

In mathematics, the derivative of a function of a real variable measures the sensitivity to change of the function value with respect to a change in its argument.

7 0

2 years ago

4. Stella says the equation x^2−8x+y^2+2y=5 has a center of (4,−1) and a radius of 5. Is she correct? Why or why not?

Ostrovityanka [42]

<h2>Stella is correct about center and wrong about radius </h2>

Step-by-step explanation:

Equation of circle with (h,k) as center and radius r is given by,

(x-h)²+(y-k)² = r²

Here equation is

x²−8x+y²+2y=5

Changing in to (x-h)²+(y-k)² = r² form

x²−8x + 16 - 16 +y²+2y+1 - 1=5

(x-4)² - 16 + (y+1)² -1 = 5

(x-4)² + (y+1)² = 22

(x-4)² + (y+1)² = 4.69²

Center is (4,-1) and radius is 4.69

Stella is correct about center and wrong about radius

8 0

2 years ago