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Rom4ik [11]
2 years ago
14

5) A not so agile track star collides with a hurdle with a force of 10,000 N.

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
8 0
The answer of this question is 25 m/s
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Three equal sides are each 4 cm in length and the has no right angles what is it
Trava [24]
THE ANSWER IS
TRIANGLE

7 0
3 years ago
Read 2 more answers
Choose one of the factors of x^3 + 343
djyliett [7]
I've done this test before 

The factor should be x+7 so, none of the above.

Hope I helped! ( Smiles )
4 0
2 years ago
A.) 170<br> B.) 300<br> C.)280<br> D.)155<br> Please help me
pav-90 [236]

Answer:

Step-by-step explanation:

The formula for this is

∠G = 1/2(arcEH - arcHF)

We have angle G (5x - 10) and we have arcEH (195) so we have to solve for x to find the measure of arcEHF so we can add arcEH + arcHF = arcEHF

Filling in the formula with what we have:

5x-10=\frac{1}{2}(195-(8x+17))

which simplifies down a bit to

5x-10=\frac{1}{2}(195-8x-17) which simplifies down a bit more to

5x-10=\frac{1}{2}(178-8x) Multiply both sides by 2 to get rid of the fraction and get:

2(5x - 10) = 178 - 8x which of course simplifies to

10x - 20 = 178 - 8x. Now add 8x to both sides and at the same time add 20 to both sides to get:

18x = 198 so

x = 11. Now we can find the measure of arcHF:

arcHF is 8x + 17, so arcHF is 8(11) + 17 which is 105°.

arcEH + arcHF = arcEHF so

195 + 105 = arcEHF so

arcEHF = 300°

6 0
3 years ago
Which statement is true about the expression?
zysi [14]

Answer:

Your number is (3 sqrt(2)) / sqrt(2) = 3, and is a rational number indeed. I don't know exactly how to interpret the rest of the question. If r is a positive rational number and p is some positive real number, then sqrt(r^2 p) / sqrt(p) is always rational, being equal r. Possibly your question refers to situtions in which sqrt(c) is not uniquely determined, as for c negative real number or complex non-real number. In those situations a discussion is necessary. Also, in general expressions the discussion is necesary, because the denominator must be different from 0, and so on.

Step-by-step explanation:

7 0
2 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B3x-6%7D%7B5-2x%7D" id="TexFormula1" title="f(x)=\frac{3x-6}{5-2x}" alt="f
Svetradugi [14.3K]

i) The given function is

f(x)=\frac{3x-6}{5-2x}

The domain is all real values except the ones that will make the denominator zero.

5-2x=0

-2x=-5

x=2.5

The domain is all real values except, x=2.5.

ii) To find the vertical asymptote, we equate the denominator to zero and solve for x.

5-2x=0

-2x=-5

x=2.5

iii) If we equate the numerator to zero, we get;

3x-6=0

3x=6

This implies that;

x=2

iv) To find the y-intercept, we put x=0 into the given function to get;

f(0)=\frac{3(0)-6}{5-2(0)}.

f(0)=\frac{-6}{5}.

f(0)=-\frac{6}{5}.

v)

The degrees of both numerator and the denominator are the same.

The ratio of the coefficient of the degree of the numerator to that of the denominator will give us the asymptote.

The horizontal asymptote  is y=-\frac{3}{2}.

vi) The function has no common factors that are at least linear.

The function has no holes in it.

vii) This rational function has no oblique asymptotes because it is a proper rational function.

3 0
3 years ago
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