Question

Find x on this special right triangle

Answer 1

Answer:

The answer is 7

Step-by-step explanation:

We know than Tan45=1

Tanx=opp/adj

tan45=y/(7$\sqrt{2}$)/2

Thus y=7$\sqrt{2}$/2

We know by pythagoras theorem that hyp^2=side^2+side^2

$x^{2}$=($(7\sqrt{2} /2)^{2}$+$(7\sqrt{2}/2)^{2}$

$x^{2}$=(49(2)/4)+(49(2)/4)

$x^{2}$=(49/2)+(49/2)

$x^{2}$=(98/2)

$x^{2}$=49

x=7