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Murrr4er [49]
3 years ago
11

The figure shows the path of a track. It consists of a semicircular arc BCD and three sides of a rectangle in which AB = 20 cm,

AE = 14 cm and DE= 20 cm.
Taking \pi to be 22/7 , Calculate

(a) the area of the figure
(b) the length of semicircular arc BCD

Mathematics
1 answer:
fredd [130]3 years ago
7 0

\large \mathcal{Answer}

A. Area of given figure = 280 + 77 = 357 cm²

B. length of semicircle = 22 cm

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Let r represent the radius of cylinder.

We have been given that the height of a right circular cylinder is 1.5 times the radius of the base. So the height of the cylinder would be 1.5r.

We will use lateral surface area of pyramid to solve our given problem.

LSA=2\pi r h, where,

LSA = Lateral surface area of pyramid,

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Upon substituting our given values in above formula, we will get:

LSA=2\pi r\cdot (1.5)r  

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TSA=2\pi r(r+h)

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\frac{TSA}{LSA}=\frac{2\pi r(2.5r)}{2\pi r(1.5r)}

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<h3>What is a linear equation?</h3>

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The linear equation is given as,

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