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Murrr4er [49]
3 years ago
11

The figure shows the path of a track. It consists of a semicircular arc BCD and three sides of a rectangle in which AB = 20 cm,

AE = 14 cm and DE= 20 cm.
Taking \pi to be 22/7 , Calculate

(a) the area of the figure
(b) the length of semicircular arc BCD

Mathematics
1 answer:
fredd [130]3 years ago
7 0

\large \mathcal{Answer}

A. Area of given figure = 280 + 77 = 357 cm²

B. length of semicircle = 22 cm

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<h3>Solution (Line 3): <u>(Refer to graph 2)</u></h3>

<u>Note that:</u>

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  • Slope formula: Rise/Run
  • Point slope form formula: y - y₁ = m(x - x₁)

To create the equation of the line, find the slope. Then, use point slope form to find the equation of the line.

<u>Use the slope formula to find the slope.</u>

  • Rise/Run = Slope
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  • => Rise/Run = -5/4

<u>Use the point slope form formula.</u>

  • y - y₁ = m(x - x₁) = Equation of line.
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