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The sum will be:
sigma(i = 1 to infinity, 30*(2/5)^i)
->
Which is equal to 30/(3/5) = 50
sigma(i = 1 to infinity, 30*(2/5)^i)
->
Which is equal to 30/(3/5) = 50
Answer:
see explanation
Step-by-step explanation:
To find the x- intercepts set y = 0, that is
- 2x² - 9x + 5 = 0
To factorise the quadratic consider the factors of the product of the coefficient of the x² term and the constant term that sum to give the coefficient of the x- term.
product = - 2 × 5 = - 10 and sum = - 9
The factors are - 10 and + 1
Use these factors to split the middle term
- 2x² - 10x + x + 5 = 0 ( factor the first/second and third/fourth terms )
- 2x(x + 5) + 1(x + 5) ( factor out (x + 5) )
(x + 5)(- 2x + 1) = 0
equate each factor to zero and solve for x
x + 5 = 0 ⇒ x = - 5
- 2x + 1 = 0 ⇒ x =
x-intercepts are x = - 5 and x =