Useful Log Rules:
- log(A*B) = log(A)+log(B) .......... log rule 1
- log(A/B) = log(A) - log(B) .......... log rule 2
- log(A^B) = B*log(A) ................... log rule 3
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Part (a)
All logs shown below are base 3.
log(500) = log(5*100)
log(500) = log(5*10^2)
log(500) = log(5)+log(10^2) .... use log rule 1
log(500) = log(5) + 2*log(10) .... use log rule 3
log(500) = 1.4650 + 2*2.096 ....... substitution
log(500) = 5.657
<h3>Answer: 5.657</h3>
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Part (b)
All logs shown below are base 3.
log(2) = log(10/5)
log(2) = log(10) - log(5) .... use log rule 2
log(2) = 2.096 - 1.4650 ....... substitution
log(2) = 0.631
<h3>Answer: 0.631</h3>
Answer: True
Step-by-step explanation:
If x2 = 49, then x = 7. True; x = 7 if and only if x^2 = 49.
I hope this solves your problem! It was a little tricky but I tried.
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Answer: 236
Explanation:
100% = 200
118% = x
-> x = (118 * 200) / 100
-> x = 236
Answer:
Time taken by the un powered raft to cover this distance is T = 192.12 hr
Step-by-step explanation:
Let speed of boat = u 
Speed of current = v
Let distance between A & B = 100 km
Time taken in downstream = 32 hours
u + v = 3.125 ------ (1)
Time taken in upstream = 48 hours
u - v = 2.084 ------- (2)
By solving equation (1) & (2)
u = 2.6045
v = 0.5205
Now the time taken by the un powered raft to cover this distance
Because un powered raft travel with the speed of the current.
T = 192.12 hr
Therefore the time taken by the un powered raft to cover this distance is
T = 192.12 hr
Answer:
( -8,27) I believe
Step-by-step explanation:
Because you times 2x2x2=8 and 3x3x3=27. Getting( -8,27)
Hope this helps :)
