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3 years ago

Tell me the answer pls need help

Mathematics

2 answers:

Volgvan3 years ago

8 0

Answer:

Step-by-step explanation:

find:

Coordinates of intersection of lines

As per the graph the intersection point has coordinates:

x = - 1, y = - 4

The point is (-1, -4)

Alika [10]3 years ago

5 0

Answer:

(-1,-4)

Step-by-step explanation:

The point (-1,-4) is where both lines intersect.

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A swimming pool is represented on a coordinate grid with the following vertices: Vertex A is at (−2,−3) . Vertex B is at (−2,

Semmy [17]

Answer:

26 yards.

Step-by-step explanation:

We can find the distance walked by Jared by finding the distances between each of the given vertex of swimming pool. We will use distance formula to find the distances between each vertex.

$\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{(-2--2)^{2}+(-3-5)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{(-2+2)^{2}+(-8)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{(0)^{2}+(-8)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{64}=8$

Now let us find distance between vertex B and vertex C.

$\text{Distance between vertex B and vertex C}=\sqrt{(-2-3)^{2}+(5-5)^{2}}$

$\text{Distance between vertex B and vertex C}=\sqrt{(-5)^{2}+(0)^{2}}$

$\text{Distance between vertex B and vertex C}=\sqrt{25}=5$

Now let us find distance between vertex C and vertex D.

$\text{Distance between vertex C and vertex D}=\sqrt{(3-3)^{2}+(5--3)^{2}}$

$\text{Distance between vertex C and vertex D}=\sqrt{(0)^{2}+(5+3)^{2}}$

$\text{Distance between vertex C and vertex D}=\sqrt{64}=8$

Now let us find distance between vertex D and vertex A.

$\text{Distance between vertex D and vertex A}=\sqrt{(3--2)^{2}+(-3--3)^{2}}$

$\text{Distance between vertex D and vertex A}=\sqrt{(3+2)^{2}+(-3+3)^{2}}$

$\text{Distance between vertex D and vertex A}=\sqrt{(5)^{2}+(0)^{2}}$

$\text{Distance between vertex D and vertex A}=\sqrt{25}=5$

Now let us add all these distances to find the total distance walked by Jared.

$\text{Total distance walked by Jared}=8+5+8+5$

$\text{Total distance walked by Jared}=26$

Since we have been given that one unit on the grid equals 1 yard, therefore, Jared walked a distance equal to 26 yards.

3 0

3 years ago

Patel squeezed oranges so that his family could have fresh-squeezed juice for breakfast. He squeezed StartFraction 4 over 17 End

dlinn [17]

Answer:

A. 1/2 cups

Step-by-step explanation:

13/15 is close to 1

1/5 is a small amount

9/20 is just over 1/2

5/11 is just under 1/2

7/15 is just under 1/2

Estimate: 1 + 1/2 + 1/2 + 1/2 + a little = 2 1/2

He needs 3 cups, so he needs another 1/2 cup.

Answer: A. 1/2 cups

5 0

3 years ago

Read 2 more answers

Number 13 least to greatest please put an order

IgorLugansk [536]

5.67, 5.68, 5.87, 6.57

6 0

2 years ago

Read 2 more answers

∫ 3 x ^2/ ( x + 1 ) ^2

lina2011 [118]

There you go. I assumed you know how to derrivate!

4 0

3 years ago

A fruit company delivers its fruit in two types of boxes: large and small. A delivery of

Tema [17]

Answer:

Small box weighs 13.75 kg & large box weighs 15.75 kg

Step-by-step explanation:

We can write 2 simultaneous equation and solve for weight of each box.

Let weight of large box be l and small box be s.

"3 large boxes and 5 small boxes has a total weight of 116 kilograms":

$3l+5s=116$

and

"9 large boxes and 7 small boxes has a total weight of 238 kilograms":

$9l+7s=238$

Now we can solve for l in the 1st equation and put it into 2nd equation and get s:

$3l+5s=116\\3l=116-5s\\l=\frac{116-5s}{3}$

now,

$9l+7s=238\\9(\frac{116-5s}{3})+7s=238\\3(116-5s)+7s=238\\348-15s+7s=238\\348-238=15s-7s\\110=8s\\s=\frac{110}{8}=13.75$

now we plug in 13.75 into s into equation of l to find s:

$l=\frac{116-5s}{3}\\l=\frac{116-5(13.75)}{3}\\l=15.75$

5 0

3 years ago