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Anna [14]
3 years ago
15

I don't get this I need help

Mathematics
1 answer:
Arada [10]3 years ago
5 0
We notice from the choices, that the problem is solved using the Pythagorean theorem somehow. How?

If ABC was a right triangle, the hypotenuse would be BC (the largest side), so the right angle would be A.

In that case we would have 54 squared (which equals 2916) equal to the sum of the squares of 22 and 51 (which equals 3085).

If the triangle was a right triangle, 22^2+51^2 would be exactly equal to 54^2, but it is larger. This means that a right angle is not large enough to 'enclose' 22^2+51^2. Thus angle A must be opened more that 90°.

Thus the answer is D:
 an obtuse triangle because  22^2+51^2>54^2

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Which statement about the points (5, 7) and (10, 12) is true?
cluponka [151]

Answer: the answer is C  because it asking does those coordinates pass thru the origin of 0,0

Step-by-step explanation:

5 0
3 years ago
A chess club with 55 members is electing a new president. Lucy received 33 votes. What percentage of the club members voted for
bonufazy [111]
You would put it up into proportions so 33 over 55 equals x over 100. Then you would cross multiply so 55x=3300. Then you would divide 3300 by 55 and get 60%.
4 0
2 years ago
Find the value of the variable (n)
alisha [4.7K]

Answer:

D. 65

Step-by-step explanation:

180-50=130

130 divided by 2 =65

hope this helps:)

5 0
3 years ago
Read 2 more answers
ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.
Ne4ueva [31]

I think the answer is (b) compress as in others , the position is changed not the shape

3 0
3 years ago
Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute
valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

       = 3 - 1 = 2

d.f.D = N - k

        = 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust                      Jet red                 Cloudtran

$\overline X_1 =50.5$           $\overline X_2 =50.07143$        $\overline X_3 =55.71429$

$s_1^2=19.96154$      $s_2^2=14.68681$         $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

         $=\frac{51+51+...+49+49}{35}$

        = 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

     $=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

   $=\frac{127.1143}{2}$

   = 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

    $=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

   $=\frac{669.8571}{32}$

  = 20.93304

The F-test  statistics value is :

$F=\frac{s_B^2}{s_W^2}$

  $=\frac{63.55714}{20.93304}$

  = 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source       Sum of squares    d.f    Mean square    F

Between    127.1143                 2      63.55714          3.036212

Within        669.8571             32      20.93304

Total           796.9714            34

3 0
2 years ago
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