The constants of a polynomial is the term that has no variable attached to it.
<h3>The constant term</h3>
To determine the constant, we simply multiply the constant term in each factor of the polynomial.
So, we have:
<h3 /><h3>Polynomial P(x) = (x-2)(x-4)(x-5)</h3>
Hence, the constant is -40
<h3>Polynomial P(x) = (x-2)(x-4)(x+5)</h3>
Hence, the constant is 40
<h3>Polynomial P(x) =1/2(x-2)(x-4)(x+5)</h3>
Hence, the constant is 20
<h3>Polynomial P(x) = 5(x-2)(x-4)(x+5)</h3>
Hence, the constant is 200
<u>P(x) =-5(x-2)(x-4)(x+5)</u>
Hence, the constant is -200
Read more about polynomials at:
brainly.com/question/2833285
Answer:
-6r+6
Step-by-step explanation:
Given data
We are given the expression
8-(6r+2)
let us expand it by opening the bracket
=8-6r-2
collect like terms
=8-2-6r
=6-6r
rearrange
=-6r+6
Hence option A is correct
Ok so the first thing to do would be get rid of the fraction. To do that multiply the ENTIRE equation but the denominator. Once all the numbers are multiplyed I think it’ll be easier for u to solve them :) or if u wanna solve them quick, download Photomath :)
V<span>ertical angles are equal.
We have 4x = 2x + 18.
Then, 2x = 18;
x = 18 </span>÷ 2;
x = 9 degrees;
The measure of angle DBE is 2 × 9 + 18 = 36 degrees.
Answer: x^2 + y^2 -10y = 0
Step-by-step explanation:
Cartesian coordinates, also called the Rectangular coordinates, isdefined in terms of x and y. So, for the problem θ has to be eliminated or converted using basic foundations that are described by the unit circle and the right triangle trigonometry.
r= 10sin(θ)
Remember that:
x= r × cos(θ)
y= r × sin(θ)
r^2= x^2 + y^2
Multiply both sides of the equation by r. This will give:
r × r = 10r × sin(θ)
r^2 = 10r × sin(θ)
x^2 + y^2= 10r × sin(θ)
Because y= r × sin(θ), we can make a substitution. This will be:
x^2 + y^2= 10y
x^2 + y^2 -10y = 0
The above equation is the Rectangular coordinate equivalent to the given equation.
