Answer: 
Remember: RISE/RUN (y/x). Lines that are increasing have a positive slope, and lines that are decreasing have a negative slope.
You can find the slope in two ways:
1. Useful if the line is graphed: count the units between 2 points on the line.
- Let's use the points (-1, 4) and (4, -4).
- (-1, 4) is 8 units higher than (4, -4) and 5 units to the left of (4, -4).
- Because the line is decreasing, the slope is negative.
- Therefore, the slope is
.
2. Useful if the line is not graphed: find the difference between the y-coordinate values divided by the difference of the x-coordinate values.
- Let's use the points (-1, 4) and (4, -4).

- Therefore, the slope is
.
Answer:
65 degrees
Step-by-step explanation:
Break the parallelogram up into two triangles. Angle E is 70 degrees and 45 degrees because of the property of equal opposite angles. So E 45 degrees Y 70 degrees and if you add the two up you get 115 degrees. There are 180 degrees in a triangle, so 180-115=65.
Answer:
602.88in²
Step-by-step explanation:
Formula for finding the volume of oblique triangle is expressed as
A = πr²h
Given
radius r = 4in
height h = 12in
Substitute
A = π*4²*12
A = 3.14*16*12
A = 3.14 * 192
A = 602.88in²
Hence the area of the cylinder is 602.88in²
Answer:
Step-by-step explanation:
(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.
(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.
(C) Example of a second order linear ODE:
M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)
The equation will be homogeneous if K(t)=0 and heterogeneous if 
Example of a second order nonlinear ODE:

(D) Example of a nonlinear fourth order ODE:
![K^4(x) - \beta f [x, k(x)] = 0](https://tex.z-dn.net/?f=K%5E4%28x%29%20-%20%5Cbeta%20f%20%5Bx%2C%20k%28x%29%5D%20%3D%200)
X = (12 +- sqrt (144 -4(7)(3))/14
x = (12 + - sqrt (144 - 84))/14
x = (12 + - sqrt(60))/14
x = (12 + - 2sqrt 15))/14
x = (6 + - sqrt 15) / 7