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2 years ago

12

To make cheer hair bows out of ribbon, Rachel needs 2 ¼ feet of ribbon. If Rachel bought 13 ½ yards of ribbon at a sale, how man

y hair bows could she make? (NS.1)

1 answer:

Citrus2011 [14]2 years ago

6 0

Answer: the answer is 5

Step-by-step explanation:

You might be interested in

The Frill family and the Smith family go to the movies.

Sati [7]

Step-by-step explanation:

Let a be the price of 1 adult ticket.

Let c be the price of 1 child ticket.

given,

$6a + 2c = 124$

as equation 1,

and

$3a + 5c = 100$

as equation 2.

Now we will solve for a and c using elimination method of simultaneous equations.

Now we multiply equation 2 by 2 to eliminate a and solve for c.

$3a \times 2 + 5c \times 2 = 100 \times 2 \\ 6a + 10c = 200$

This new equation will be equation 3.

Now we will use equation 1 - equation 3 to eliminate a and solve for c.

$(6a - 6a) + (2c - 10c) = 124 - 200 \\ 0 + ( - 8c) = - 76 \\ - 8c = - 76 \\ c = - 76 \div - 8 \\ = 9.5$

Now substitute c into equation 2.

$3a + 5(9.5) = 100 \\ 3a + 47.5 = 100 \\ 3a = 100 - 47.5 \\ 3a = 52.5 \\ a = 52.5 \div 3 \\ = 17.5$

Therefore one adult ticket will cost $17.50 and one child ticket will cost $9.50.

7 0

2 years ago

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon

fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that $n = 603, \pi = \frac{142}{603} = 0.2355$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694$

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

8 0

2 years ago

Zigmanuir [339]

The converted the percentage to a decimal the wrong way.

Move the decimal point 2 places to the left.

6.5% as a decimal is 0.065

525.05 x 0.065 = 34.13

X = 34.13

4 0

3 years ago

Please help me with this question

Y_Kistochka [10]

Answer:

2(a - 4) + 5(b + 1) = 8. The result of this equation when solving is a = - 5b/2 + 11/2.

3(a - 1) - 2(b - 2) = -11. The result of this equation when solving is a = 2b/3 - 4.

Step-by-step explanation:

Hope this helps =)

8 0

2 years ago

A warehouse ships cans of soup weighing 19 oz each in a box that weighs 6 oz. Which gives the weight of a shipped box containing

Effectus [21]

The weight of the cans is 19 oz and each box weighs 6 oz. The answer is D, 19n + 6 is the weight of a shipped box..

5 0

2 years ago