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Vera_Pavlovna [14]
2 years ago
14

What is 10x as much as 70?​

Mathematics
1 answer:
sleet_krkn [62]2 years ago
5 0

9514 1404 393

Answer:

  700

Step-by-step explanation:

You figure this out by multiplying 70 by 10:

  10×70 = 700

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Alex777 [14]
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3 years ago
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The cost of using a game facility is $1 for every 12 minutes. Talisa writes the function for the cost per hour as ()=. Explain T
Anna [14]

Using proportions, it is found that Talisa's error was at calculating the cost per minute of the game.

In the function:

  • The input is x, which is the number of minutes.
  • The output is f(x), which is the cost of playing the game for x minutes.

Talisa's expression is given by:

f(x) = 12x

The cost of using a game facility is <u>$1 for every 12 minutes</u>, hence, the cost per minute is:

c = \frac{1}{12}

And the correct expression for the cost is:

f(x) = \frac{x}{12}

Hence, it can be seen that Talisa's error was at calculating the cost per minute of the game.

A similar problem is given at brainly.com/question/24372153

3 0
2 years ago
The vertex of an isosceles triangle measures 15 degrees more than one of its base angles how many degrees are there in a base an
Alexxandr [17]
V=B+15
V+2B=180
Therefore:
3B+15=180
B=55
V=70

Check:
V+2B=180
70+2(55)=180
70+110=180
180=180. Checks. 
5 0
3 years ago
What is the lcm of 81 and 17?​
algol [13]

Answer:

1377

Step-by-step explanation:

The least common multiple (LCM) of two or more non-zero whole numbers is the smallest whole number that is divisible by each of those numbers. In other words, the LCM is the smallest number that all of the numbers divide into evenly.

3 0
2 years ago
Jason and Maria are playing a board game in which three dice are tossed to determine a player's move. Find each probability for:
fredd [130]
Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,

P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216. 

P(three 5s) = (1 x 1 x 1)/216   = 1/216

P(one 5 or two 5s)  = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
6 0
3 years ago
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