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ikadub [295]
3 years ago
10

Type the correct answer in each box. Use numerals instead of words,

Mathematics
1 answer:
xeze [42]3 years ago
8 0

Answer:

x = -6,3,15,-12; y = 11,5,-3,15

Step-by-step explanation:

Domain is the x value, so plugged in the x values into the equation and got the y values or range.

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Expand & simplify: (x - 5)(x + 2)
Serjik [45]

Answer:

( x - 5 )( x + 2 )

= x² + 2x - 5x - 10

= x² - 3x - 10

7 0
3 years ago
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Please answer correctly, will give brainly to best answer, please do explain your answer
Liono4ka [1.6K]

Answer: 26

2³ + 4(2 + x) for x = 10

- first do 4(2 + x) which is

8+4x

- Evaluate 2 cubed

You get 2 times 2 times 2.

That would get 8

Our expression is 8 + 8+x

x = 10

Substitute the values.

It is Now eight plus 8 plus ten

So when you Calculate eight plus 8 plus 10

You will get 26

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3 years ago
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What is a quick way to determine which savings account will pay the most interest?
Igoryamba
I would say, the best way and the fastest way, is to go to some banks and ask them how much interests they give you... then the bank that gives you the most interest, the bank that you are looking for. 
6 0
3 years ago
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A box contains 20 light box of which five or defective it for lightbulbs or pick from the box randomly what's the probability th
Snowcat [4.5K]

Answer:

1

Step-by-step explanation:

Given:-

- The box has n = 20 light-bulbs

- The number of defective bulbs, d = 5

Find:-

what's the probability that at most two of them are defective

Solution:-

- We will pick 2 bulbs randomly from the box. We need to find the probability that at-most 2 bulbs are defective.

- We will define random variable X : The number of defective bulbs picked.

Such that,               P ( X ≤ 2 ) is required!

- We are to make a choice " selection " of no defective light bulb is picked from the 2 bulbs pulled out of the box.

- The number of ways we choose 2 bulbs such that none of them is defective, out of 20 available choose the one that are not defective i.e n = 20 - 5 = 15 and from these pick r = 2:

        X = 0 ,       Number of choices = 15 C r = 15C2 = 105 ways

- The probability of selecting 2 non-defective bulbs:

      P ( X = 0 ) = number of choices with no defective / Total choices

                       = 105 / 20C2 = 105 / 190

                       = 0.5526

- The number of ways we choose 2 bulbs such that one of them is defective, out of 20 available choose the one that are not defective i.e n = 20 - 5 = 15 and from these pick r = 1 and out of defective n = 5 choose r = 1 defective bulb:

        X = 1 ,       Number of choices = 15 C 1 * 5 C 1 = 15*5 = 75 ways

- The probability of selecting 1 defective bulbs:

      P ( X = 1 ) = number of choices with 1 defective / Total choices

                       = 75 / 20C2 = 75 / 190

                       = 0.3947

- The number of ways we choose 2 bulbs such that both of them are defective, out of 5 available defective bulbs choose r = 2 defective.

        X = 2 ,       Number of choices = 5 C 2 = 10 ways

- The probability of selecting 2 defective bulbs:

      P ( X = 2 ) = number of choices with 2 defective / Total choices

                       = 10 / 20C2 = 10 / 190

                       = 0.05263

- Hence,

    P ( X ≤ 2 ) = P ( X =0 ) + P ( X = 1 ) + P (X =2)

                     = 0.5526 + 0.3947 + 0.05263

                     = 1

7 0
3 years ago
Can Somone help me please.
leonid [27]

Answer: Perimeter of a Triangle Formula Equilateral Triangle Formula

Acute angled Triangle Isosceles Triangle Perimeter Formula

Step-by-step explanation:

7 0
2 years ago
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