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blondinia [14]
3 years ago
7

Please answer this really fast.

Mathematics
2 answers:
solniwko [45]3 years ago
8 0

Answer:2x(3-1) +3(3x-1)

6x^2 -2x+9x-3

6x^2+7x-3

a=6 b=7 c=3

product (x)=6x7x-3=-126

dolphi86 [110]3 years ago
4 0

Answer:

abc = - 126

Step-by-step explanation:

(2x + 3)(3x - 1) ← expand product using FOIL

= 6x² + 7x - 3 ← in standard form

with a = 6, b = 7, c = - 3

Then

abc = 6 × 7 × (- 3) = - 126

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Solve the system of equations for the variables: 5x+2y=13 x+2y=9
r-ruslan [8.4K]

Answer:

x = 1

y = 4

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5x + 2y = 13

x + 2y = 9

Add both equations.

6x + 4y = 22

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6x = 22 - 4y

x = 22/6 - 4/6y

Put x as 22/6 - 4/6y in the second equation and solve for y.

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4 0
3 years ago
Read 2 more answers
See question in screenshot below.
alexgriva [62]

The equation of the transformation of the exponential function <em>y</em> = 2ˣ in the form <em>y</em> = A·2ˣ + k, obtained from the simultaneous found using the points on the graph is <em>y</em> = (-2)·2ˣ + 3

<h3>What is an exponential equation?</h3>

An exponential equation is an equation that has exponents that consists of variables.

The given equation is <em>y</em> = 2ˣ

The equation for the transformation is; <em>y</em> = A·2ˣ + k

The points on the graphs are;

(0, 1), (1, -1) and (2, -5)

Plugging the <em>x </em>and <em>y</em>-values to find the value <em>A</em> and <em>k</em> gives  the following simultaneous equations;

When <em>x</em> = 0, <em>y</em> = 1, therefore;

1 = A·2⁰ + k = A + k

1 = A + k...(1)

When <em>x</em> = 1, <em>y</em> = -1, which gives;

-1 = A·2¹ + k

-1 = 2·A + k...(2)

Subtracting equation (1) from equation (2) gives;

-1 - 1 = 2·A - A + k - k

-2 = A

1 = A + k, therefore;

1 = -2 + k

k = 2 + 1 = 3

k = 3

Which gives;

y = -2·2ˣ + 3 = 3 - 2·2ˣ

Learn more about the solutions to simultaneous equations here:

brainly.com/question/26310043

#SPJ1

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