Volume of Cylinder V = πr²h
diameter = 6 feet, radius = 6/2 = 3 feet
dV/dt = (dV/dh) * (dh/dt) by change rule.
V = <span>πr²h
dV/dh = </span>πr² = π*3² = 9π ft²<span>
dV/dt = 2 ft</span>³/min
<span>dV/dt = (dV/dh) * (dh/dt)
</span>
2 ft³/min = 9π ft² * (dh/dt)
9π ft² * (dh/dt) = 2 ft<span>³/min
</span>
(dh/dt) = (2 ft³/min)/(9π ft<span>²)
(dh/dt) = (2/</span>9π) ft/min
So the water level is rising at (2/9<span>π) ft/min.</span>
Answer:
56π = 175.929, so no.
Step-by-step explanation:
Surface area formula: 2B+Ph (where B is area of the base, P is perimeter of the base, and h is height.)
2(4π) + 4π(12)
8π +48π
56π = 175.9 ft^2
Answer:
(a) Stratified
(b) Systematic
(c) Cluster
Step-by-step explanation:
Answer:
The cost of one ticket would be <u>$</u><u>2</u><u>.</u><u>5</u><u>,</u> the equation I believe is <u>9</u><u>x</u><u> </u><u>+</u><u> </u><u>1</u><u>3</u><u>.</u><u>5</u><u>0</u><u> </u><u>=</u><u> </u><u>3</u><u>6</u><u>.</u>
Step-by-step explanation:
I hope this helps.
<span>2g^3-g^2-8g+4
= g^2(2g - 1) - 4(2g - 1)
=(2g - 1)(g^2 - 4)
= (2g - 1)(g + 2)(g - 2)</span>
