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Leto [7]
2 years ago
5

£8001 is shared equally between 9 people. How much does each person get?

Mathematics
1 answer:
Alika [10]2 years ago
5 0
£888.9 because you can divide £8001 buy 9
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The difference between two numbers is 9 and the product of the numbers is 162. Find the two numbers
fiasKO [112]
Let the no be X and Y

acc to ques....

x-y=9 .........1

xy=162 ..........2

substituting value from 1 in 2 we get;

x=9+y

[9+y][y] = 162

y^2+9y = 162

y^2 + 9y - 162=0

y^2 + 18y - 9y - 162=0

y[y+18] + 9[y+18]=0

[y+9][y+18}

y= -9.................................3


y= -18......................................4



case 1 :

y= -9

x = 9-9=0

case 2:

y= -18

x= 9-18 = -9
7 0
3 years ago
Please help me photo include
nikklg [1K]

Answer:

\frac{-117}{10}

Step-by-step explanation:

1) Change the mixed fractions into improper fractions:

-3\frac{1}{5} + (-8\frac{1}{2} )\\= \frac{-16}{5} - \frac{17}{2}

2) Multiply the first fraction by 2/2 and the second fraction by 5/5 in order to create common factors on the denominator (You can do this because you are essentially multiplying by one, for example 2/2 = 1):

\frac{-16}{5} *\frac{2}{2}  - \frac{-17}{2} * \frac{5}{5} \\ =\frac{-32}{10} - \frac{85}{10}

3) Simplify the numerator(top part) while keeping the denominator(bottom part) the same:

\frac{-32}{10} -\frac{85}{10}  \\\\=\frac{-32 - 85}{10}\\ \\= \frac{-117}{10}

5 0
3 years ago
Please help with this, tysm ​
Sauron [17]
You just find out what the missing variable is by subtracting 88 from 107 on the first one. You do the same for the last too as-well, but just insert the numbers that they say.

Happy Friday!!
3 0
3 years ago
Read 2 more answers
Solve this inequality.<br> 8x + 6 x 54
sergeinik [125]
8x+324 is the answer, all you have to do is multiple 6 times 54
4 0
3 years ago
Read 2 more answers
When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let
sergiy2304 [10]

Answer:

(a) P(X=3) = 0.093

(b) P(X≤3) = 0.966

(c) P(X≥4) = 0.034

(d) P(1≤X≤3) = 0.688

(e) The probability that none of the 25 boards is defective is 0.277.

(f) The expected value and standard deviation of X is 1.25 and 1.089 respectively.

Step-by-step explanation:

We are given that when circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%.

Let X = <em>the number of defective boards in a random sample of size, n = 25</em>

So, X ∼ Bin(25,0.05)

The probability distribution for the binomial distribution is given by;

P(X=r)= \binom{n}{r} \times p^{r}\times (1-p)^{n-r}  ; x = 0,1,2,......

where, n = number of trials (samples) taken = 25

            r = number of success

            p = probability of success which in our question is percentage

                   of defectivs, i.e. 5%

(a) P(X = 3) =  \binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}

                   =  2300 \times 0.05^{3}\times 0.95^{22}

                   =  <u>0.093</u>

(b) P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

= \binom{25}{0} \times 0.05^{0}\times (1-0.05)^{25-0}+\binom{25}{1} \times 0.05^{1}\times (1-0.05)^{25-1}+\binom{25}{2} \times 0.05^{2}\times (1-0.05)^{25-2}+\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}

=  1 \times 1 \times 0.95^{25}+25 \times 0.05^{1}\times 0.95^{24}+300 \times 0.05^{2}\times 0.95^{23}+2300 \times 0.05^{3}\times 0.95^{22}

=  <u>0.966</u>

(c) P(X \geq 4) = 1 - P(X < 4) = 1 - P(X \leq 3)

                    =  1 - 0.966

                    =  <u>0.034</u>

<u></u>

(d) P(1 ≤ X ≤ 3) =  P(X = 1) + P(X = 2) + P(X = 3)

=  \binom{25}{1} \times 0.05^{1}\times (1-0.05)^{25-1}+\binom{25}{2} \times 0.05^{2}\times (1-0.05)^{25-2}+\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}

=  25 \times 0.05^{1}\times 0.95^{24}+300 \times 0.05^{2}\times 0.95^{23}+2300 \times 0.05^{3}\times 0.95^{22}

=  <u>0.688</u>

(e) The probability that none of the 25 boards is defective is given by = P(X = 0)

     P(X = 0) =  \binom{25}{0} \times 0.05^{0}\times (1-0.05)^{25-0}

                   =  1 \times 1\times 0.95^{25}

                   =  <u>0.277</u>

(f) The expected value of X is given by;

       E(X)  =  n \times p

                =  25 \times 0.05  = 1.25

The standard deviation of X is given by;

        S.D.(X)  =  \sqrt{n \times p \times (1-p)}

                     =  \sqrt{25 \times 0.05 \times (1-0.05)}

                     =  <u>1.089</u>

8 0
2 years ago
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