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2 years ago

If figure 1 is 3 then what is figure 100th

Mathematics

1 answer:

Alexxx [7]2 years ago

8 0

A) 3x100= 300 since figure 1 is 3 then figure 100 is 3x100

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The area of triangle

adoni [48]

The area of a triangle is area=1/2•base•height or a= b•h / 2

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3 years ago

one day in December the temperature in London was -3 degrees Celsius in Stockholm it was -5 degrees it was -8 degrees Celsius wh

lara [203]

The weather in the three areas were all very similar on that day in particular.

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2 years ago

bill is in a class of 50 students.40% of the students in the class take the bus to school. How many students do not take the bus

deff fn [24]

Answer:

Step-by-step explanation:

100%-40%=60%

but 50 is half of 100 you half 60% to 30 people

8 0

3 years ago

A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along

mina [271]

Answer:

The tip of the man shadow moves at the rate of $\frac{20}{3} ft.sec$

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

$\frac{y - x}{y} = \frac{6}{15}$

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = $\frac{15x}{9\\} y = \frac{5x}{3}$

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

$\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt}$ ----(1)

We are given $\frac{dx}{dt} = 4 ft/sec$ . Plug in the equation (1), we get

$\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec$

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

7 0

2 years ago

What is the value of a in the diagram below?

adell [148]

Answer:

a=8

Step-by-step explanation:

We can use ratios of similar triangles to solve

The smaller triangle has sides a and 12 and the larger triangle has sides a+a+4 and 12+18 which combine to 2a+4 and 30

a 2a +4

--------- = -----------

12 30

Using cross products

30a = 12(2a+4)

30a = 24a +48

Subtract 24a from each side

30a -24a = 24a-24a +48

6a = 48

Divide each sdie by 6

6a/6 =48/6

a =8

7 0

2 years ago