Answer:

Step-by-step explanation:
∵ The volume of the pyramid = 1/3 base area × height
∵ The base is equilateral Δ with side length 4
∴ The area of the bast = 1/4 × 4² × √3 = 4√3 units²
To get the height of the pyramid draw it from the vertex of the top of the pyramid ⊥ to the base on the centro-id of the base which divides the height of the triangle two ratio 2:1 from the vertex of the triangle
∵ The height of the base = √(4² - 2²) =√12 = 2√3
∴ 2/3 the height = 4√3/3 ⇒ (2:1 means 2/3 from the height)
∴ The height of the pyramid = √[4² - (4√3/3)²] = √[16 - 48/9]
∴ h = 4√2/√3 (4√6/3 in its simplest form)
∴ V = 1/3 × 4√3 × 4√2/√3 = 16√2/3 units³
∴ 
We know the slope is -1, because perpendicular line's slopes are always the negative reciprocal. We plug (5, -3) in to get:
-3 = -5 + b
b = 2
So we get C. y = -x + 2.
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Hope this helps!
==jding713==
11 seconds behind after 22 days
Its
C. Draw a line connecting the the intersection of the arcs below and above the segment.