Name the marked angle in 2 different ways.
2 answers:
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Answer:
f(x) = 3 + 2
Step-by-step explanation:
Given G(x) =
As we can see, the graph of f(x) is 2 units above the graphof g(x) in vertical (vertical shift)
=> f(x) = a + 2
As you can see, the graph of f(x) is stretched vertically by a dilation factor of 3
and there is no reflection, so a= 3
=> the equation of f(x) is: f(x) = 3 + 2
Write the equation of the line passing through the two points. Show that this line is perpendicular to the given line.
(4,1) and (6,-5) y=1/3x-7
(1,-6) and (3,-10) y=1/2x-5
Please help, we learned this today and I’m really confused. How do you do it?
(4,1) and (6,-5) y=1/3x-7
(1,-6) and (3,-10) y=1/2x-5
Please help, we learned this today and I’m really confused. How do you do it?
Answer:
We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.
Step-by-step explanation:
We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.
Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.
Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.
- Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).
- Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).
- Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).
- Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).
So, the number of passwords with 4 different digits we can write = = 360 possibilities.
Hence, we can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.