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fredd [130]
3 years ago
6

How do you solve this if you are solving for y y=3xy-1

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
6 0
Move all y terms to both sides
subtract both sides by 3xy

<span>y=3xy-1
y - 3xy = -1

factor out y from the left side: y(1 - 3x) = -1
divide both sides by (1-3x)

y = -1/(1-3x)
</span>
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PLSSS ANSWER!!!!!!!!!!!!
Brums [2.3K]

Look at the picture.


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A_\Delta=\dfrac{1}{2}ab\sin\alpha


In the equilateral triangle, the measures of all angles are the same and equal to 60°.


Therefore your answer is:


\dfrac{1}{2}aa\sin(60^o)=\dfrac{1}{2}a^2\sin(60^o)

5 0
4 years ago
Lindsay is 5 years younger than Mark. Seven years ago, the sum of their ages was 31.
Rashid [163]

Answer:

The present age of Mark is 25 years.

And present age of Lindsay is  20 years.

Step-by-step explanation:

Let us assume:

The present age of Lindsay = l

The present age of Mark = m

⇒ Age of Lindsay seven years ago =  (l -7) years

and Age of Mark seven years ago =  (m -7) years

According to question:

Lindsay is 5 years younger than Mark    ⇒   l = m  - 5

Seven years ago, the sum of their ages was 31  ⇒  (l-7) + (m -7)  = 31

So, the given set of equation are:

l = m  - 5    .........  (1)

(l-7) + (m -7)  = 31

⇒ ((m - 5) -7) + (m -7)  = 32  (from (1)

or, m -12 + m - 7  = 31

or, 2m = 31 + 19 = 50

⇒ m = 50 / 2  = 25, or m  = 25

Hence,the present age of Mark = 25 years

So,the present age of Lindsay = 25 - 5 = 20 years

7 0
3 years ago
Log base2 log base 25
UkoKoshka [18]
I think it’s 5. Since logarithms are used to find the original value of a power. Therefore you reverse it and do square root of 25 which is +5 or -5
4 0
3 years ago
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True [87]
Your friend sold (5w + 1) subscriptions.
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The difference between what your friend sold and what you sold is
(5w + 1 ) - (3w + 4)
= 5w + 1 - 3w - 4
= 5w - 3w + 1 - 4
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Answer: 2w - 3

3 0
4 years ago
Read 2 more answers
You roll two dice.what is the probability you get a 2 and a number greater than 2
almond37 [142]

Answer:dice one will be 2 than dice two could be 3,4,5,6...etc

Step-by-step explanation: 2<3 and 2<4 etc

6 0
4 years ago
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