This problem is fairly simple if you know the exponential equation, you start with y=78(.17)^x. the you put 10=78(.17)^x, then you solve for x
10=78(.17)^x
-78
-68=.17^x
divide .17 then you have your answer!!
Answer:
Town C.
Step-by-step explanation:
Average change of population with time for town A = 
Average change of population with time for town B = 
Average change of population with time for town C = 
Average change of population with time for town D = 
Town C had the greatest average change in population over time (800/yr).
If these both men were working at normal hours, and then, (John) worked "2 more hours" than Gary has, this would just mean that he has worked more.
x+2= x+2.
Now if John has worked the double amount, 4 more times than Gary's usual hours, this would mean something quite different.
Then the expression would look like, (x+2×4x)
We don't know how many hours are the "usual hours", this is what "x" would then represent.
John has then worked (4×2+x) more hours than Gary.
Your answer: (4×2+x)
Do 23.3 times 93 that should lead you in the right direction
*I could be wrong but this is what I think it is*
1,200 divided by 150. That equals 8, then multiply 8 by 30. Answer is 240