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3 years ago

Will mark brainlist if right

Mathematics

1 answer:

yarga [219]3 years ago

3 0

Answer:

It will be an infinite amount, so i think its no solutions

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Answer and show work #38

Serggg [28]

Did you get your answer yet

6 0

3 years ago

PLEASE HELP ASAP ITS GEOMETRY

Gwar [14]

The missing options that makes up the distance formula between two coordinates are; (x₂ - x₁)² and d²

How to find the distance between two coordinates?

The formula for distance between two coordinates is;

d = √[(y₂ - y₁)² + (x₂ - x₁)²]

where;

(x₁, y₁) is the coordinate of the first point

(x₂, y₂) is the coordinate of the second point

Now, this distance formula can also be rewritten when we square both sides to get;

(y₂ - y₁)² + (x₂ - x₁)² = d²

Thus, the missing options that makes up the distance formula between two coordinates are; (x₂ - x₁)² and d²

Read more about distance between two coordinates at; brainly.com/question/7243416

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2 years ago

Scott runs on a daily basis. He runs 3.2 miles every day except Saturday, when he runs 7 miles. How many miles will he jog in th

Ksenya-84 [330]

Answer:

It's 78.6

Step-by-step explanation:

I hope this helps you

7 0

3 years ago

A container holds 2 quarts of lemonade how much is this in cups?

soldier1979 [14.2K]

I think that it might be 24 cups

7 0

4 years ago

Read 2 more answers

Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/4, 1/2

siniylev [52]

<u>Answer:</u> The probability that Xavier and Yvonne can solve a problem but Zelda cannot is $\frac{3}{64}$

<u>Step-by-step explanation:</u>

We are given:

Probability of success of Xavier, $P(S)_{Xavier}=\frac{1}{4}$

Probability of failure of Xavier, $P(F)_{Xavier}=1-\frac{1}{4}=\frac{3}{4}$

Probability of success of Yvonne, $P(S)_{Yvonne}=\frac{1}{2}$

Probability of failure of Yvonne, $P(F)_{Yvonne}=1-\frac{1}{2}=\frac{1}{2}$

Probability of success of Zelda, $P(S)_{Zelda}=\frac{5}{8}$

Probability of failure of Zelda, $P(F)_{Zelda}=1-\frac{5}{8}=\frac{3}{8}$

We need to calculate:

The probability that Xavier and Yvonne can solve the problem but Zelda cannot, we use:

$P(S)_{Xavier}\times P(S)_{Yvonne}\times P(F)_{Zelda}=\frac{1}{4}\times \frac{1}{2}\times \frac{3}{8}=\frac{3}{64}$

Hence, the probability that Xavier and Yvonne can solve a problem but Zelda cannot is $\frac{3}{64}$

6 0

3 years ago