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Nady [450]
3 years ago
9

Find (2x + 3y) 2a 4x2+12xy+9y2 b 4x2+9y2 c 4x2+12+9y2​

Mathematics
1 answer:
lilavasa [31]3 years ago
7 0

Answer:

a

Step-by-step explanation:

(2x + 3y)²

= (2x + 3y)(2x + 3y)

Each term in the second factor is multiplied by each term in the first factor

2x(2x + 3y) + 3y(2x + 3y) ← distribute parenthesis

= 4x² + 6xy + 6xy + 9y² ← collect like terms

= 4x² + 12xy + 9y² → a

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The point P(18, 24) is on the terminal side of θ. Evaluate sin θ.
serious [3.7K]
<span>sin θ = opposite/hypotenuse
P(18,24) lies in the first quadrant as both are positive.
x=18
y=24
Hypotenuse  = sqrt (18^2 + 24^2)
</span><span>Hypotenuse = 30
</span><span>sin θ = 24/30
</span><span>sin θ = 4/5
</span>θ = sin^-1 (4/5) 
<span>θ = 53.13 degrees</span>
7 0
3 years ago
Read 2 more answers
What is the sum of the areas of circle C and circle D?
Yanka [14]

Answer:

98pi

Step-by-step explanation:

Area of circle: pi(r)^2

A1=pi(7)^2

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A2+A1=98pi

4 0
3 years ago
the hypotenuse of a right triangle is 3 cm and one of the legs is 1 cm what is the length of the other leg ?
Afina-wow [57]

Answer:

2\sqrt{2}

Step-by-step explanation:

let the other leg be x

Using Pythagoras' identity

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² + 1² = 3²

x² + 1 = 9 ( subtract 1 from both sides )

x² = 8 ( take the square root of both sides )

x = \sqrt{8}

  = \sqrt{4(2)}

  = \sqrt{4} × \sqrt{2} = 2\sqrt{2} ← exact value

4 0
3 years ago
Math homework please help ​
-BARSIC- [3]
F nbc hbbb b bbb. hey n b
6 0
2 years ago
A cube-shaped box has a volume of 125 cubic inches. If the box is packed full of cubes with edge lengths of 1 inch, how many cub
harina [27]

I am not sure if I am right, but this is the best I can answer.


Useing reason, and logic, my guess would be if you take 125, and divided it by 4, you would get 31.25. that should be the answer... if i am wrong, i am truely sorry. I havent been in the subject in a while...


                                                           Hope this helps.


6 0
3 years ago
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