The minimum surface area that such a box can have is 380 square
<h3>How to determine the minimum surface area such a box can have?</h3>
Represent the base length with x and the bwith h.
So, the volume is
V = x^2h
This gives
x^2h = 500
Make h the subject
h = 500/x^2
The surface area is
S = 2(x^2 + 2xh)
Expand
S = 2x^2 + 4xh
Substitute h = 500/x^2
S = 2x^2 + 4x * 500/x^2
Evaluate
S = 2x^2 + 2000/x
Differentiate
S' = 4x - 2000/x^2
Set the equation to 0
4x - 2000/x^2 = 0
Multiply through by x^2
4x^3 - 2000 = 0
This gives
4x^3= 2000
Divide by 4
x^3 = 500
Take the cube root
x = 7.94
Substitute x = 7.94 in S = 2x^2 + 2000/x
S = 2 * 7.94^2 + 2000/7.94
Evaluate
S = 380
Hence, the minimum surface area that such a box can have is 380 square
Read more about surface area at
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In exponential form: 10^2=3(x+5)
If we were to solve, x=85/3
Answer:
x^15
Step-by-step explanation:
Recall these rules of exponents:
(a^m)^n = a^mn
a^m • a^n = a^(m + n)
(x^6)² • x³ = x^(2 • 6) • x³ = x^12 • x³ = x^(12 + 3) = x^15
Answer:
The center is (-10,10) and the radius is 4sqrt(3)
Step-by-step explanation:
(x + 10)^2 + (y - 10)^2 = 48
We can write the equation of a circle as
(x -h)^2 + (y - k)^2 = r^2 where (h,k) is the center and r is the radius
(x- -10)^2 + (y - 10)^2 = (sqrt(16*3) )^2
(x- -10)^2 + (y - 10)^2 = (4sqrt(3)) ^2
The center is (-10,10) and the radius is 4sqrt(3)
Answer:
Step-by-step explanation:
The answer is 5blocks to the right and 3 blocks up thank me LATER
