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3 years ago

Help plz nd thanks!!!!

Mathematics

1 answer:

choli [55]3 years ago

3 0

Plug in the value
6(3)^2 + 2(3) + 10
6(9) + 6 + 10
54 + 6 + 10
60 + 10 = 70
The solution is 70

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Huw has a maths test. the second question is:

xeze [42]

Huw's answer of 9 days is incorrect because more guests would finish the food in less time so the number of days for 30 guests is less than 6 days.

The number of days that the food can last 30 guests is 4 days.

<h3>How long will Seaview Hotel's food feed 30 guests?</h3>

More guests would eat the food faster which means that it would be finished in less days than the 6 days used by 20 guests.

To find the days the food would last 30 guests, use the inverse proportion formula:
= (Number of guests x Number of days food lasts for guests) / New number of guests

= (20 x 6) / 30

= 4 days

Full question is:

The only food provided for guests at Seaview Hotel is breakfast. The hotel has enough food to make breakfast for 20 guests for 6 days. How long would the food last 30 guests? You may assume each guest eats the same amount of food for breakfast.

Without working out the correct answer, explain why Huw’s answer of 9 days is incorrect.

Find out more on inverse proportion at brainly.com/question/1266676.

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5 0

2 years ago

Suppose a poker hand contains seven cards rather than five. Compute the probabilities of the following poker hands: (a) a seven-

geniusboy [140]

Answer:

a) 0.00031

b) 0.0017

c) 0.31

d) 0.00018

Step-by-step explanation:

attached below is the detailed solution

Total number of 7-poker cards are 52P7 = 133784560

A) Determine the probabilities of Seven-card straight

probability of seven-card straight = 0.00031

B) Determine the probability of four cards of one rank and three of a different rank

P( four cards of one rank and three of different rank ) = 0.0017

C) Determine probability of three cards of one rank and two cards of each two different ranks

P( three cards one rank and two cards of two different ranks ) = 0.31

D) Determine probability of two cards of each of three different ranks and a card of a fourth rank

P ( two cards of each of three different ranks and a card of fourth rank ) = 0.00018

8 0

3 years ago

Select an operation to make the equation true.

MrRa [10]

Add. I’m not sure because there is a - besides the 15.

Explanation - 12 + 15 = 27.

Hopefully this helps. Have a blessed one. God loves you. ☺️

3 0

3 years ago

If f x = 7x<br><br> 2 − 4x − 10, then f −3 =?

Schach [20]

Answer:

f(x)=xy3 -4xy2 -7x+10

Step-by-step explanation:

the xy3 and xy2 means x to the 3rd power and x to the second power

7 0

3 years ago

16) Please help with question. WILL MARK BRAINLIEST + 10 POINTS.

Katyanochek1 [597]

We will use the sine and cosine of the sum of two angles, the sine and consine of $\frac{\pi}{2}$ , and the relation of the tangent with the sine and cosine:

$\sin (\alpha+\beta)=\sin \alpha\cdot\cos\beta + \cos\alpha\cdot\sin\beta

\cos(\alpha+\beta)=\cos\alpha\cdot\cos\beta-\sin\alpha\cdot\sin\beta$

$\sin\dfrac{\pi}{2}=1,\ \cos\dfrac{\pi}{2}=0$

$\tan\alpha = \dfrac{\sin\alpha}{\cos\alpha}$

If you use those identities, for $\alpha=x,\ \beta=\dfrac{\pi}{2}$ , you get:

$\sin\left(x+\dfrac{\pi}{2}\right) = \sin x\cdot\cos\dfrac{\pi}{2} + \cos x\cdot\sin\dfrac{\pi}{2} = \sin x\cdot0 + \cos x \cdot 1 = \cos x$

$\cos\left(x+\dfrac{\pi}{2}\right) = \cos x \cdot \cos\dfrac{\pi}{2} - \sin x\cdot\sin\dfrac{\pi}{2} = \cos x \cdot 0 - \sin x \cdot 1 = -\sin x$

Hence:

$\tan \left(x+\dfrac{\pi}{2}\right) = \dfrac{\sin\left(x+\dfrac{\pi}{2}\right)}{\cos\left(x+\dfrac{\pi}{2}\right)} = \dfrac{\cos x}{-\sin x} = -\cot x$

3 0

4 years ago