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For this case we have the following function:
F (x) = 3x ^ 2 + 6x-24
We observe that it is a quadratic equation.
The graph is therefore a parabola.
Its cut points are:
(-4, 0)
(2, 0)
Answer:
See attached image to see graph of the function
F (x) = 3x ^ 2 + 6x-24
We observe that it is a quadratic equation.
The graph is therefore a parabola.
Its cut points are:
(-4, 0)
(2, 0)
Answer:
See attached image to see graph of the function
Given:
m(ar KN) = 2x + 151
m(ar LN) = 61°
m∠NMK = 2x + 45
To find:
m∠NMK
Solution:
By property of circle:
<em>If a tangent and a secant intersect outside a circle, then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.</em>
Multiply by 2 on both sides, we get
Subtract 90 from both sides.
Subtract 2x from both sides.
Substitute x= 0 in m∠NMK.
m∠NMK = 2x + 45
= 2(0) + 45
= 45
Therefore m∠NMK = 45.