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Vedmedyk [2.9K]
3 years ago
8

Number 13 please. I really need help.

Mathematics
1 answer:
laiz [17]3 years ago
8 0

Answer:

There is no solution.

Step-by-step explanation:

Math

Way

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How many permutations exist of the letters a, b, c, d taken two at a time?
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The number of permutations of the 4 different letters, taken two at a time, is given by:
4P2=\frac{4!}{2!}=12
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BG and AB

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Which underfined geometric term can be described as a one dimensional
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Hello from MrBillDoesMath!

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A point.



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4 years ago
Simplify 5p2/5p3<br><br> a) p/4<br> b) 3p3<br> c) 1/p<br> d) 6/7p3
Alex73 [517]

To simplify the above expression, we can use the quotient rule.

\frac{x^a}{x^b} =x^(a-b)

By using the above property we can subtract the exponents of the same base.

First step is to simplify the above expression, cancel out 5 from both numerator and denominator. Therefore,

\frac{5p^2}{5p^3} =\frac{p^2}{p^3}

=p^{2-3}

= p^-1

= \frac{1}{p}

Since x^-1 = \frac{1}{x}.

So, the correct choice is c) 1/p.

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5 0
3 years ago
Ben consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Ben's body decr
Airida [17]

Answer:

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

Step-by-step explanation:

After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.

This means that the amount of caffeine after t hours is given by:

A(t) = A(0)e^{-kt}

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.

1 - 0.2722 = 0.7278, thus, A(10) = 0.7278A(0). We use this to find k.

A(t) = A(0)e^{-kt}

0.7278A(0) = A(0)e^{-10k}

e^{-10k} = 0.7278

\ln{e^{-10k}} = \ln{0.7278}

-10k = \ln{0.7278}

k = -\frac{\ln{0.7278}}{10}

k = 0.03177289938&#10;

Then

A(t) = A(0)e^{-0.03177289938t}

What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body?

We have to find find A(5), as a function of A(0). So

A(5) = A(0)e^{-0.03177289938*5}

A(5) = 0.8531

The decay factor is:

1 - 0.8531 = 0.1469

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

7 0
3 years ago
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